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  • Rik Hodiamont 56 posts 156 karma points
    May 03, 2011 @ 13:50
    Rik Hodiamont
    0

    Level 3 navigation

    I am new to XSLT and I'm having a problem generating a sublevel menu.

    I'm using the following structure:

    Menu-item 1

       Page 1

          SubPage 1

          SubPage 2

      Page 2

    Menu-item 2

    When i'm on subpage 2 I want a list of all the pages under Page 1. So I thought I could generate a list based on the parentID. But somehow that won't work:

    This is the code I'm using:

    <xsl:template match="/">
      <xsl:for-each select="$currentPage/@parentID/* [@isDoc and string(umbracoNaviHide) != '1']">
      <li>
        <a href="{umbraco.library:NiceUrl(@id)}">
          <xsl:value-of select="@nodeName"/>
        </a>
      </li>
    </xsl:for-each>
    </xsl:template>

    Thanks in advance.

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  • Fuji Kusaka 2203 posts 4220 karma points
    May 03, 2011 @ 13:53
    Fuji Kusaka
    0

    Hi Rik,

    Do you mean you are making a Top Nvagitaion Menu with 3 levels?

    Fuji

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  • Rik Hodiamont 56 posts 156 karma points
    May 03, 2011 @ 13:56
    Rik Hodiamont
    0

    Hi Fuji,

    No, i want that if the user is on SubPage 2, he sees a list of all the pages under the parent page (page 1).

    So in this example the user sees a list of SubPage 1 and SubPage 2.

    Tnx!

    Rik

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  • Fuji Kusaka 2203 posts 4220 karma points
    May 03, 2011 @ 14:08
    Fuji Kusaka
    0

    Rik,

    So you are looking for something like a breadcrumb but instead it will display the list of items under page1 ~ Subpage 1 + Subpage 2?

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  • praveity 100 posts 125 karma points
    May 03, 2011 @ 14:14
    praveity
    0

    Hi Fuji,

    You could try this out.

    Here it will loop through all the child nodes (including itself) within the same parent node.

    This way you could get both subpage 1 and subpage 2, being at subpage 1 or subpage 2

    <xsl:for-each select="$currentPage/parent::*[@isDoc]//*[@isDoc]">
    <li>
        <a href="{umbraco.library:NiceUrl(@id)}">
          <xsl:value-of select="@nodeName"/>
        </a>
      </li>
    </xsl:for-each>
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  • Rik Hodiamont 56 posts 156 karma points
    May 03, 2011 @ 14:18
    Rik Hodiamont
    0

    Fuji, Praveity thank you a lot. It works!!

    For future reference: Where is the @isDoc value for?

    Tnx!

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  • Fuji Kusaka 2203 posts 4220 karma points
    May 03, 2011 @ 14:20
    Fuji Kusaka
    0

    Rik,

    Try this out by using a XSLT breadCrumb.

     

    <xsl:if test="$currentPage/@level &gt; $minLevel">
          <ul>
              <xsl:for-each select="$currentPage/descendant::*[@isDoc]">
               <li>
                <a href="{umbraco.library:NiceUrl(@id)}">
                  <xsl:value-of select="@nodeName"/>
                </a>
              </li>
            </xsl:for-each>            
          </ul>
        </xsl:if>
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  • Rik Hodiamont 56 posts 156 karma points
    May 03, 2011 @ 15:08
    Rik Hodiamont
    0

    Tnx Fuji. Both solutions worked :)

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