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Hi There,
I have a sub navigation on the side of my pages. I'm wanting to get the parent node name of the current page. How can I do this?
Thanks in advance.
Sean
<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp " "> ]><xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxml="urn:schemas-microsoft-com:xslt" xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" xmlns:tagsLib="urn:tagsLib" xmlns:BlogLibrary="urn:BlogLibrary" exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets tagsLib BlogLibrary "><xsl:output method="xml" omit-xml-declaration="yes"/><xsl:param name="currentPage"/><xsl:template match="/"><!-- The fun starts here --><ul><xsl:for-each select="$currentPage/* [@isDoc and string(umbracoNaviHide) != '1']"> <li> <a href="{umbraco.library:NiceUrl(@id)}"> <xsl:value-of select="@nodeName"/> </a> </li></xsl:for-each></ul></xsl:template></xsl:stylesheet>
Hi,
This will get you the parent nodename of the current page outside of your loop
<xsl:value-of select="$currentPage/parent::*[@isDoc]/@nodeName"/>
There would be no point getting the parent of the pages within your loop, as they would just be the current page.
Rich
is working on a reply...
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getting the parent node name
Hi There,
I have a sub navigation on the side of my pages. I'm wanting to get the parent node name of the current page. How can I do this?
Thanks in advance.
Sean
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp " "> ]>
<xsl:stylesheet
version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxml="urn:schemas-microsoft-com:xslt"
xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" xmlns:tagsLib="urn:tagsLib" xmlns:BlogLibrary="urn:BlogLibrary"
exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets tagsLib BlogLibrary ">
<xsl:output method="xml" omit-xml-declaration="yes"/>
<xsl:param name="currentPage"/>
<xsl:template match="/">
<!-- The fun starts here -->
<ul>
<xsl:for-each select="$currentPage/* [@isDoc and string(umbracoNaviHide) != '1']">
<li>
<a href="{umbraco.library:NiceUrl(@id)}">
<xsl:value-of select="@nodeName"/>
</a>
</li>
</xsl:for-each>
</ul>
</xsl:template>
</xsl:stylesheet>
Hi,
This will get you the parent nodename of the current page outside of your loop
<xsl:value-of select="$currentPage/parent::*[@isDoc]/@nodeName"/>
There would be no point getting the parent of the pages within your loop, as they would just be the current page.
Rich
is working on a reply...