I've got a content item called Knowledgebase that contains several articles.  I'm trying to work on an XSLT document rather than a .NET User Control to show these nodes.  I don't want to use currentPage as the default loop over since I ONLY want it to loop over Knowledgebase articles.  I have the following code working:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [
  <!ENTITY nbsp " ">
]>
<xsl:stylesheet
  version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:umbraco.library="urn:umbraco.library"
  xmlns:Level2Course.XsltExtensions.SyntaxHighlighter="urn:Level2Course.XsltExtensions.SyntaxHighlighter"
  exclude-result-prefixes="msxml umbraco.library Level2Course.XsltExtensions.SyntaxHighlighter">
 
  <xsl:output method="xml" omit-xml-declaration="yes"/>
 
  <xsl:param name="currentPage"/> 
    <xsl:template match="/">
  <ul>
  <xsl:for-each select="$currentPage/child::* [@parentID = 1073]">
    <li>
      <a class="navigation" href="{umbraco.library:NiceUrl(@id)}"><span><xsl:value-of select="@nodeName"/></span></a>
    </li>
  </xsl:for-each>
  </ul>
</xsl:template>
 
</xsl:stylesheet>

The problem is, I don't want the parent ID hardcoded - I want to be able to copy and paste this into other sites.  

Thanks in advance for any help.

Also, does Umbraco keep track of the number of "hits" an item receives?  Is it possible to sort the nodes by most popular?  Thanks!