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  • Fuji Kusaka 2203 posts 4220 karma points
    May 25, 2011 @ 12:30
    Fuji Kusaka
    0

    Displaying a Nodes in SiteMap with by using template

    Hi Guys,

    I have multiple folders under my Content Node and am trying to get my XSLT Site map to display the nodes which are under a folder and using this piece of code but am not getting the node displayed.

    Any Suggestions?

     

    <xsl:variable name="maxLevelForSitemap" select="4"/>

    <xsl:template match="/">
    <div id="sitemap"> 
      <xsl:call-template name="drawNodes">  
          <xsl:with-param name="parent" select="$currentPage/ancestor-or-self::* [@isDoc and @level=1]"/>  
      </xsl:call-template>
    </div>
    </xsl:template>

    <xsl:template name="drawNodes">
    <xsl:param name="parent"/> 
    <xsl:if test="umbraco.library:IsProtected($parent/@id, $parent/@path) = 0 or (umbraco.library:IsProtected($parent/@id, $parent/@path) = 2 and umbraco.library:IsLoggedOn() = 1)">
    <ul>

      <xsl:for-each select="$parent/* [@isDoc and @level &lt;= $maxLevelForSitemap and string (@template) !='0' and name()  !='folder1
    ']"> 
      <li>  
        <a href="{umbraco.library:NiceUrl(@id)}"> <xsl:value-of select="@nodeName"/> </a>  
      
      <xsl:if test="count(./* [@isDoc and  @level &lt;= $maxLevelForSitemap and string (@
    template)  !='0' and name ()  != 'folder1']) &gt; 0">   
        <xsl:call-template name="drawNodes">    
            <xsl:with-param name="parent" select=""/>    
        </xsl:call-template>  
      </xsl:if> 
    </li>
        
        
    </xsl:for-each>
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