I am able to get the username of all editors however what I ecaxtly need is their ids (memberId). Is there any way to acheive that via XSLT. Any other ideas how to approach that result would be welcome.
I was woundering if you got a solution for your problem. I've got the same problem. Only get the login name using ucomponents.members:GetMembersByGroupName('Editors')
GetMembersByGroupName('name') will only return the usernames, so no luck with this method and no other xslt extension exists to fetch the memberid as well. But should be straightforward to write your own xslt extension to return id's instead of usernames (or both). Grab the ucomponents source and write your own extension based on the ucomponents code...
Get all members by specific group in XSLT
Ηello all,
Using the ucomponents members extension
ucomponents.members:GetMembersByGroupName('Editors')
I am able to get the username of all editors however what I ecaxtly need is their ids (memberId). Is there any way to acheive that via XSLT. Any other ideas how to approach that result would be welcome.
Thanks, Giorgos
Hi Giorgos,
I was woundering if you got a solution for your problem. I've got the same problem. Only get the login name using ucomponents.members:GetMembersByGroupName('Editors')
Looking forward to hear.
Best regards
Palle
Giorgos,
GetMembersByGroupName('name') will only return the usernames, so no luck with this method and no other xslt extension exists to fetch the memberid as well. But should be straightforward to write your own xslt extension to return id's instead of usernames (or both). Grab the ucomponents source and write your own extension based on the ucomponents code...
Cheers,
/Dirk
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