Assuming that you want those to display on the Alumni-page, you could simply use for-eaches.

<!-- Loop through the currentPages children of type AwardCategory -->
<xsl:for-each select="$currentPage/AwardCategory">
      <!-- Loop through the children of AwardCategory of type AwardWinner-Full -->
      <xsl:for-each select="./AwardWinner-Full">
      </xsl:for-each>
</xsl:for-each>

Does this make sense or do I not understand your structure right?

Peter

I am actually posting all of this information on the Awards page. But I did use your line:

<xsl:for-each select="./AwardWinner-Full">

which I think will work to answer PART 1 of my issue... just the tricky is part left! ;-)
I'll give ya a High Five though for that

Part 2 shouldn't be that hard either then ;)

<xsl:for-each select="./AwardWinner-Full[ @year = $year ]">

@year is the property-name of the awardwinner and $year is the selected year on the parent. I'm not sure how the xml is structered on the tags, but if you do a xsl:copy-of then you'll get the entire xml spit out 

Does this get you going? If not, post a bit xml from the copy-of so I can see the properties. I can then make a bit better xslt :)

Peter

Hello Peter,

I've been working to intergrate that second part to my script this morning but I haven't had any luck yet. I'm wondering if because my indiviual award winner is using the tags datatype that it might not be going as smoothly as I had hoped. Of course I might just be missing it too.. So here's what I got working..

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet
  version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" xmlns:tagsLib="urn:tagsLib" xmlns:BlogLibrary="urn:BlogLibrary" xmlns:PS.XSLTsearch="urn:PS.XSLTsearch"
  exclude-result-prefixes="msxml
 umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes 
Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings 
Exslt.ExsltSets tagsLib BlogLibrary PS.XSLTsearch ">

<xsl:output method="xml" omit-xml-declaration="yes" />

<xsl:param name="currentPage"/>
<xsl:template match="/">
<xsl:for-each select="umbraco.library:GetXmlNodeById(1876)/AwardCategory">
  <h2><xsl:value-of select="@nodeName"/></h2>
  <xsl:value-of select="awardCategoryDescription"/>
  <P>
    The <xsl:value-of select="umbraco.library:FormatDateTime(umbraco.library:CurrentDate(), 'yyyy')"/> Award recipients are:
  </P>  
      

     <xsl:for-each select="./AwardWinner-Full">
        <li>
          <xsl:value-of select="@nodeName"/> class of '<xsl:value-of select="umbraco.library:FormatDateTime(awardWinnerGraduatingYear, 'yy')"/>
          <BR><xsl:value-of select="awardWinnerDepartment"/></BR>
          <xsl:value-of select="awardWinnerJobTitle"/> | <xsl:value-of select="awardWinnerCompany"/>
                  
        </li>
      </xsl:for-each>

  
<P><a href="{umbraco.library:NiceUrl(@id)}">ARCHIVE LINK</a></P>
</xsl:for-each>
</xsl:template>  
</xsl:stylesheet>

The alias for the Award Category Display Year is = displayAwardsWinners (which is a dropdownlist single selection)
and the alias for the Individual persons winning years is = awardWonTheseYears (which is a TAG dataType)

Thanks for your help.

Yeah, looks like that did the trick. They both seem to work quite well. Thanks Tom

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