Hey Lars,

In my opinion you should (if you're not too far down the road) change the structure of your site to:

--- start (home)

--------- page 1

--------------- subpage 1

--------------- supbage 2

--------- page 2

--------- page 3

This will mean that all the default scripts will run much nicer, the way your structure is set up at the moment will cause you no end of problems (in my opinion).

Rich

Hi Rich

Thank you for your quick answer.

I am shure that making another level will make a solution but it must be possible to include the "start" page in a XSLT generated menu. I would still like to know how!

Lars

Change the variable to 0 I think.

Rich

YES tbe code below works. It helps to look at what other and wiser people have done, so I fount the solution at http://our.umbraco.org/forum/using/ui-questions/16583-Need-help-with-sub-navigation-XSLT

But thank you anyway Rich for your help!

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet
  version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets"
  exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets ">

<xsl:output method="xml" omit-xml-declaration="yes" />

<xsl:param name="currentPage"/>
    
   <xsl:variable name="rootNode" select="$currentPage/ancestor-or-self::*[@level=1]" />
<xsl:template match="/">
    <ul id="subMenu">
      <li>
        <a href="{umbraco.library:NiceUrl($rootNode/@id)}">
            <xsl:value-of select="$currentPage/ancestor-or-self::*[@level = '1']/@nodeName"/>
        </a>
      </li>
        <xsl:apply-templates select="$rootNode/*[@isDoc and string(umbracoNaviHide) != '1']"/>
 
    </ul>
</xsl:template>  

<xsl:template match="*[@isDoc and string(umbracoNaviHide) != '2']">
    <xsl:variable name="id" select="id" />
    <li class="subNiveau">
        <xsl:attribute name="class">subNiveau<xsl:if test="$currentPage/ancestor-or-self::*/@id = current()/@id"> current</xsl:if></xsl:attribute>
        <a href="{umbraco.library:NiceUrl(./@id)}">
          <xsl:value-of select="@nodeName" />
        </a>
    </li>
    <xsl:if test="count(./*[@isDoc and string(umbracoNaviHide) != '1']) &gt; 0 and count(descendant-or-self::*[@id = $currentPage/@id]) &gt; 0">
        <li class="nav">
            <ul>        
              <xsl:apply-templates select="./*[@isDoc and string(umbracoNaviHide) != '1']" />        
          </ul>
        </li>  
    </xsl:if>
</xsl:template>
 

</xsl:stylesheet>

Hey. Can anyone explain me how to start a new topic in the Umbraco forum? It should be quite straightforward but I am lost. I have an Umbraco forum profile already. Regards, Lars

Hey Lars,

First you select the category on this page

Then you get to this page where you can see the 'Create a new topic' button

Hope this helps.

Rich

Hey Rich

Thank you very much and yes, it helped me. Now I just need to learn the rest of Umbraco :-).

Lars

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