simple xslt problem with xslfor each select=$currentpage - XSLT

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Garry Bain 149 posts 124 karma points

Sep 06, 2011 @ 14:51
0

Simple XSLT problem with xsl:for-each select="$currentPage"

XSLT
Hi everyone,

I currently have a macro showing news items on the home page. This works fine when placed on the home page as the path is correctly pointing towards my articles:
```
<xsl:for-each select="$currentPage/*/umbNewsArticle [@isDoc]">
```
```
<xsl:value-of select="introduction" disable-output-escaping="yes"/>
```
```
<p><a href="{umbraco.library:NiceUrl(@id)}">Read More</a></p>
```
```
</xsl:for-each> 
```
However, as soon as I go to a different page, the information disappears - as the $currentPage/*/umbNewsArrticle is now pointing to the wrong place.

How can I adjust my code so that the select statement will always point to the same place. My site structure is as follows:

Home

        - News Landing Page

                         - News Item 1

                         - News Item 2

                         - News Item 3

Any help would be brilliant, cheers.
Garry.
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Bas Schouten 135 posts 233 karma points

Sep 06, 2011 @ 14:58

0

Hi Garry,

Try this one: http://our.umbraco.org/wiki/reference/umbracolibrary/getxmlnodebyid

Bas

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Fuji Kusaka 2203 posts 4220 karma points

Sep 06, 2011 @ 15:04

Hi Gary you could change your XSLT code to something like

 <xsl:variable name="source" select="1200"/> 

<xsl:template match="/">
 <xsl:for-each select="umbraco.library:GetXmlNodeById($source)/* [@isDoc and string(umbracoNaviHide) != '1']">
 <xsl:value-of select="introduction"disable-output-escaping="yes"/>
 <p><a href="{umbraco.library:NiceUrl(@id)}">Read Morea>p>
 
</xsl:template>

Hope this helps

//fuji

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Dirk De Grave 4541 posts 6021 karma points MVP 3x admin c-trib

Sep 06, 2011 @ 15:08

3

Or use,

<xsl:value-ofselect="introduction"disable-output-escaping="yes"/>
<xsl:for-eachselect="$currentPage/ancestor-or-self::* [@level = 1]//* [name() = 'umbNewsArticle']">
<p><ahref="{umbraco.library:NiceUrl(@id)}">Read Morea>p>
xsl:for-each>

which will travel up your tree until it finds a node at level 1 (=Home) and find all descendants (regardless of level) of type umbNewsArticle.

Cheers,

/Dirk

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Garry Bain 149 posts 124 karma points

Sep 06, 2011 @ 15:11

0

Thank you both very much.

Fixed it with Fuji's code - thanks!

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Anthony Candaele 1197 posts 2049 karma points

Sep 06, 2011 @ 15:25

0

personally I more like Dirk's code because it is more generic (you don't need to hard code the id).

greetings,

Anthony

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Simple XSLT problem with xsl:for-each select="$currentPage"