Hi,

I have the below XSLT which is grabbing the values selected by a multi-node-tree-picker on the children of the homepage of my site. Is there a way to separate the children in the XSLT? I'd like to put each of them into a separate list instead of having one list containing all of the values of the pickers. I'm not sure how to say "for each child do this, then for each of their children do this"

So right now I get:

Homepage

• item 1 from child 1
• item 2 from child 1
• item 1 from child 2
• item 2 from child 2

What I'd like to achieve is

Div

• Item 1 from child 1
• item 2 from child 1

Div

• Item 1 from child 2
• item 2 from child 2

<xsl:if test="$currentPage/topStories/MultiNodePicker/nodeId">

    <ul>

      <!-- Loop through each of the nodeId values -->
      <xsl:for-each select="$currentPage/* [@isDoc and string(umbracoNaviHide) != '1']/topStories/MultiNodePicker/nodeId">

        <!--
 Since we only have the nodeId value, we need to get the actual content 
node using umbraco.library's GetXmlNodeById method -->
        <!--
 If you prefer to use pure XPath, then used this: 
"$currentPage/ancestor-or-self::*[@isDoc and @level = 
1]/descendant-or-self::*[@isDoc and @id = current()]" -->
        <xsl:variable name="node" select="umbraco.library:GetXmlNodeById(.)" />
        <li>

          <!-- Output the URL using umbraco.library's NiceUrl method -->
          <a href="{umbraco.library:NiceUrl(.)}">

            <xsl:value-of select="$node/@nodeName" />

          </a>

        </li>
      </xsl:for-each>

    </ul>

  </xsl:if>

Thanks for your help!

Amir