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  • Craig 2 posts 22 karma points
    Oct 14, 2011 @ 23:26
    Craig
    0

    Schoolboy error or is something wrong with my output?

    I’m using Umbraco 4.7.0

    My goal is to get the image path from a hard coded media node id of 4191. If I create a new macro with the code:

    <xsl:copy-of select="umbraco.library:GetMedia(4191, false())"/>

    I get the output:

    /media/17675/my image.jpg50033618497jpg

    I was expecting some well formed xml, however, it appears I’m missing all the tags. I therefore cannot reference the path for the image directly.

    Am I missing something really simple here?

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  • bob baty-barr 1180 posts 1294 karma points MVP
    Oct 15, 2011 @ 00:32
    bob baty-barr
    1

    are you putting the output in a textarea? or viewing the source output of the page?

    you can actually get the image path by using

    <xsl:vaule-of select="umbraco.library:GetMedia(4191,false())/umbracoFile"/>

    You can then use something like this to actually render the image in your html

    <xsl:variable name="picFile" select="umbraco.library:GetMedia(4191,false())/umbracoFile"/>
    <xsl:if test="$picFile != '' ">
    <img src="{$picFile}"/>
    </xsl:if>
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  • Craig 2 posts 22 karma points
    Oct 15, 2011 @ 07:46
    Craig
    0

    Thank you bob baty-barr. 

    I discovered how to get the raw xml output from my `copy-of` statement. I needed to wrap it in a `<textarea>` tag:  

      <textarea>
              <xsl:copy-ofselect="umbraco.library:GetMedia(4191, false())"/>
     </textarea>

    Thank to this post

     

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