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  • Jordy Vialoux 73 posts 103 karma points
    Nov 20, 2011 @ 20:52
    Jordy Vialoux
    0

    XSLT Get Sub Page

    Hi Guys,

    I have a site where I have a Products page where it lists a heap of brands so for example "Nike, Addidas, Converse" etc

    You click on a brand then it lists all the products for that brand. Each list item has a heading, copy and an image.

    The client wants to create a content page underneath that product.

    Tree structure will look like this -

    Products ( Lists brands )
         Product ( Lists Products )
              Product Content

    How can I get the user to the "product content" page from the "product page" ?

    On both Products and Product pages where they list more than one item I am using <xsl:for each> statement. Each item is then listed within a UL.

    Here is my code to assist:

    All suggestions welcome!

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  • Richard 146 posts 168 karma points
    Nov 21, 2011 @ 15:44
    Richard
    0

    To get the URL to a page use:

    <a href="{umbraco.library:NiceUrl(@id)}">Link test</a>

    So you could change line 20:

    <a href="{umbraco.library:NiceUrl(@id)}" ><xsl:value-of select="productName"/></a>

     

    Richard

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