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  • Carlos 338 posts 472 karma points
    Dec 22, 2011 @ 19:19
    Carlos
    0

    XSLT, Content Picker, get Properties

    I am using the content picker to choose a content page from another page in the content tree.

    In my XSLT I am trying to get a property from my chosen Node I chose from my content picker.

    I am able to output the ID of the node by using

    <xsl:value-of select="umbraco.library:GetXmlNodeCurrent()/courseClassroomResource"/>

    I set up some custom properties that I would like to pull from the node. Like... "My Page Title".

    I thought I would be able to get my property by doing

    <xsl:value-of select="umbraco.library:GetXmlNodeCurrent()/courseClassroomResource/myPageTitle"/>

     

    But this outputs nothing on the page.  

    Does anyone have any ideas why this may be happening or can anyone point me in the right direction?

    Thanks.

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  • Tom Fulton 2030 posts 4998 karma points c-trib
    Dec 22, 2011 @ 19:35
    Tom Fulton
    0

    Hi,

    Here's how you should do it, using umbraco.library:GetXmlNodeById:

    <xsl:variable name="pickedPage" select="umbraco.library:GetXmlNodeById(courseClassroomResource)" />
    <xsl:if test="not($pickedPage/error)"> <!-- make sure the page still exist -->
      Name of picked page:  <xsl:value-of select="$pickedPage/@nodeName"/>
      And whatever other properties... <xsl:value-of select="$pickedPage/someProperty" />
    </xsl:if>

    -Tom

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