grouping nodes in list

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Claushingebjerg 939 posts 2574 karma points

Jan 19, 2012 @ 10:38

Hi im trying to wrap subpages from an id in pairs of 2, but im kinda stuck.
So any pointer would be very nice.
Right now i have the following code, which i read up on somewhere, but i think either my scpoping or matching is off.

<xsl:variable name="source" select="1056"/>
<xsl:variable name="n" select="number(2)"/>

<xsl:template match="/">
  <div id="testimonials">
    <xsl:apply-templates select="umbraco.library:GetXmlNodeById($source)/node [position() mod $n = 1]"/>
</div>
</xsl:template>  
  
<xsl:template match="node">
<div class="clients-testimonials">
  <xsl:for-each select=". | following-sibling::item[position() &lt; $n]">
    <blockquote>
      Output node values here
    </blockquote > 
  </xsl:for-each>
</div>    
</xsl:template>        
</xsl:stylesheet>

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Rodion Novoselov 694 posts 859 karma points

Jan 19, 2012 @ 11:01

Hi. It can be done e.g. the following way:

  <xsl:for-each select="$node/*[@isDoc][string(umbracoNaviHide) != '1']">
    <xsl:if test="position() mod 2 = 1">
      <xsl:value-of select="'&lt;div&gt;'" disable-output-escaping="yes"/>
    </xsl:if>
    <p>
    <xsl:value-of select="@nodeName"/>
    </p>
    <xsl:if test="position() mod 2 = 0 or position() = last()">
      <xsl:value-of select="'&lt;/div&gt;'" disable-output-escaping="yes"/>
    </xsl:if>
  </xsl:for-each>

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Chriztian Steinmeier 2800 posts 8791 karma points MVP 8x admin c-trib

Jan 19, 2012 @ 11:07

Hi Claus,

In your node template you're selecting <item> siblings - probably a typo, right? Try this instead:

<xsl:variable name="source" select="1056" />
<xsl:variable name="n" select="2" />

<xsl:template match="/">
    <div id="testimonials">
        <xsl:apply-templates select="umbraco.library:GetXmlNodeById($source)/node[position() mod $n = 1]" />
    </div>
</xsl:template>  

<xsl:template match="node">
    <div class="clients-testimonials">
        <xsl:for-each select=". | following-sibling::node[position() &lt; $n]">
            <blockquote>
                Output node values here
            </blockquote> 
        </xsl:for-each>
    </div>
</xsl:template>

/Chriztian

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Claushingebjerg 939 posts 2574 karma points

Jan 19, 2012 @ 11:36

0

Hmmm Chriztian.
It still doesnt work.It renders the main div "Testemonials" but doesnt render "client-testemonials" at all.

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Chriztian Steinmeier 2800 posts 8791 karma points MVP 8x admin c-trib

Jan 19, 2012 @ 11:42

0

Hi Claus - works on my machine :-)

Ok, you're using the old schema, right? (Hence the "node" element)

/Chriztian

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Claushingebjerg 939 posts 2574 karma points

Jan 19, 2012 @ 11:43

0

no, im on 4.7.1

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Chriztian Steinmeier 2800 posts 8791 karma points MVP 8x admin c-trib

Jan 19, 2012 @ 11:48

OK - that explains it - you need to use *[@isDoc] instead of node (or better: If they're all the same Document Type - use the alias, e.g.: Testimonial)

<xsl:templatematch="/">
               <divid="testimonials">
                <xsl:apply-templatesselect="umbraco.library:GetXmlNodeById($source)/*[@isDoc][position() mod $n = 1]"/>
                </div>
        </xsl:template>  

        <xsl:templatematch="*[@isDoc]">
                <divclass="clients-testimonials">
                        <xsl:for-eachselect=". | following-sibling::*[@isDoc][position() &lt; $n]">
                                <blockquote>
                                        <xsl:value-ofselect="@nodeName"/>
                                </blockquote> 
                        </xsl:for-each>
                </div>
        </xsl:template>

/Chriztian

EDIT: Updated to use GetXmlNodeById()

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Claushingebjerg 939 posts 2574 karma points

Jan 19, 2012 @ 12:52
0
im going crazy!

Ive copy/pasted your code, but it still doesnt render the inner div... Ive been staring at it for ages, but cant seem to find any errors!

Doing a normal
```
<xsl:for-each select="umbraco.library:GetXmlNodeById(1056)/* [@isDoc and string(umbracoNaviHide) != '1']">
      <xsl:value-of select="@nodeName"/>
</xsl:for-each>
```
Works fine, so the nodes are published and accessible...
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Rodion Novoselov 694 posts 859 karma points

Jan 19, 2012 @ 12:57

0

It seems there's a misspelling - "node" means any node with the name "node".

To select all nodes you need to spell it as "node()".

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Chriztian Steinmeier 2800 posts 8791 karma points MVP 8x admin c-trib

Jan 19, 2012 @ 13:00

0

Hi Claus,

My bad!! Really - I forgot to use GetXmlNodeById() - (on my local machine I use something else that doesn't work in Umbraco context).

I've updated the code above - please try again.

@Rodion: "node" in this context is actually from the old XML Schema in Umbraco; Bit confusing, yes, if you're used to XSLT :-)

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Claushingebjerg 939 posts 2574 karma points

Jan 19, 2012 @ 13:05
0
SUCCESS!!!! i thought
```
//*
```
was som kind of fancy shorthand :)
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Chriztian Steinmeier 2800 posts 8791 karma points MVP 8x admin c-trib

Jan 19, 2012 @ 13:12

0

It's a very bad shorthand - but works fine when you've only got a small set of nodes for testing :-)

/Chriztian

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abhijeetwaychal 5 posts 25 karma points

Dec 02, 2012 @ 14:40

0

Thanks Chriztian and Claus

Updatd XSLT worked at it is with modifcation //*

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