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  • Peter Grillo Frederiksen 34 posts 67 karma points
    Jan 24, 2012 @ 22:08
    Peter Grillo Frederiksen
    1

    Vimeo file not found - problem

    Hey All,

    I'm creating an image gallery, where I also uses Vimeo-videos.
    It's no problem to create thumbnails for the pictures.

    For creating thumbnails for Vimeo, I use this code:

    <xsl:variable name="Vimeopath" select="concat('http://vimeo.com/api/v2/video/1234.xml')" />
    <xsl:variable name="VimeoInfo" select="document($Vimeopath)" />

    <img src="{$VimeoInfo/videos/video/thumbnail_medium}" height="95px" border="0" />

    Easy-Piecy.

    The problem arises, when the Vimeo-file is either password-protected or does not exist.
    How do I check to see, if the Vimeo-file exists?

    If you se the above link to Vimeo, you get an error: "666 not found."
    And if you use the above code, the XSLT will not run.

    Can anybody help me?
    Cheers

    Peter

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  • Peter Grillo Frederiksen 34 posts 67 karma points
    Jan 24, 2012 @ 22:09
    Peter Grillo Frederiksen
    0

    BTW...

    "666 not found." off course is only when you use "666" instead of "1234" in the xml-link.

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  • Rodion Novoselov 694 posts 859 karma points
    Jan 24, 2012 @ 23:25
    Rodion Novoselov
    1

    Hi. Maybe this would help:

    <xsl:variable name="Vimeopath" select="'http://vimeo.com/api/v2/video/1234.xml'" />
    <xsl:variable name="VimeoInfo" select="umbraco.library:GetXmlDocumentByUrl($Vimeopath)" />
    <xsl:if test="not($VimeoInfo/error)">
        <img src="{$VimeoInfo/videos/video/thumbnail_medium}" height="95px" border="0" />
    </xsl:if>
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  • Peter Grillo Frederiksen 34 posts 67 karma points
    Jan 25, 2012 @ 09:15
    Peter Grillo Frederiksen
    0

    Rodion, your the man!!
    Thx a LOT! 

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