vimeo file not found problem - XSLT

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Peter Grillo Frederiksen 34 posts 67 karma points

Jan 24, 2012 @ 22:08
1

Vimeo file not found - problem
Hey All,

I'm creating an image gallery, where I also uses Vimeo-videos.
It's no problem to create thumbnails for the pictures.

For creating thumbnails for Vimeo, I use this code:
```
<xsl:variable name="Vimeopath" select="concat('http://vimeo.com/api/v2/video/1234.xml')" />
<xsl:variable name="VimeoInfo" select="document($Vimeopath)" />

<img src="{$VimeoInfo/videos/video/thumbnail_medium}" height="95px" border="0" />
```
Easy-Piecy.

The problem arises, when the Vimeo-file is either password-protected or does not exist.
How do I check to see, if the Vimeo-file exists?

If you se the above link to Vimeo, you get an error: "666 not found."
And if you use the above code, the XSLT will not run.

Can anybody help me?
Cheers

Peter
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Peter Grillo Frederiksen 34 posts 67 karma points

Jan 24, 2012 @ 22:09

0

BTW...

"666 not found." off course is only when you use "666" instead of "1234" in the xml-link.

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Rodion Novoselov 694 posts 859 karma points

Jan 24, 2012 @ 23:25

Hi. Maybe this would help:

<xsl:variable name="Vimeopath" select="'http://vimeo.com/api/v2/video/1234.xml'" />
<xsl:variable name="VimeoInfo" select="umbraco.library:GetXmlDocumentByUrl($Vimeopath)" />
<xsl:if test="not($VimeoInfo/error)">
    <img src="{$VimeoInfo/videos/video/thumbnail_medium}" height="95px" border="0" />
</xsl:if>

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Peter Grillo Frederiksen 34 posts 67 karma points

Jan 25, 2012 @ 09:15

0

Rodion, your the man!!
Thx a LOT!

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Vimeo file not found - problem