get all id parent from currentpage

Go to solution

Press Ctrl / CMD + C to copy this to your clipboard.

Copied to clipboard

Flag this post as spam?

This post will be reported to the moderators as potential spam to be looked at

Cristian 24 posts 45 karma points

Mar 02, 2012 @ 02:32

0

Get all id parent from currentPage

Hi everybody

there is a way to get all parent id Node from a certain node?

for example

node 1

node2

node3

node4

node5.....

and i choose node4, but i need to know all id parents, node1-node2-node4

there is a function in umbraco.library or some recursive templete to do this??

regards.

Copy Link
Markus Johansson 1936 posts 5864 karma points MVP 2x c-trib

Mar 02, 2012 @ 07:32

0

Are you talking about something lika a breadcrumb? I think that theres a build in template for that. But something like this:

<xsl:for-each select="$currentPage/ancestor::* [@level > $minCrumbLevel and string(umbracoNaviHide) != '1']">
   <li>
<a href="{umbraco.library:NiceUrl(@id)}">
   <xsl:value-of select="@nodeName"/>
   </a>
</li>
</xsl:for-each>

Copy Link
Chriztian Steinmeier 2800 posts 8790 karma points MVP 8x admin c-trib

Mar 02, 2012 @ 15:20
1
Hi Cristian,

If you just need the Ids for some reason, you can grab the @path attribute - it contains a "path of Ids" to the selected node, e.g.:
```
If you have this setup:

Home (id:1050)
  Node1 (id:1052)
    Node2 (id:1053)
    Node3 (id:1054)
    Node4 (id:1055)

You can try:
<xsl:value-of select="$currentPage/@path" /> 
```
But you don't need the Ids if you just want to access the actual nodes - the ancestor-or-self:: axis will select them for you:
```
<xsl:variable name="nodesInPathToCurrent" select="$currentPage/ancestor-or-self::*[@isDoc]" />
```
/Chriztian
Copy Link
Cristian 24 posts 45 karma points

Mar 02, 2012 @ 15:39

0

Thanks for you reply! both of you.

@path was the property that i was looking for!

Copy Link
is working on a reply...

Please Sign in or register to post replies

Flag this post as spam?