get all id parent from currentpage

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Cristian 24 posts 45 karma points

Mar 02, 2012 @ 02:32

0

Get all id parent from currentPage

Hi everybody

there is a way to get all parent id Node from a certain node?

for example

node 1

node2

node3

node4

node5.....

and i choose node4, but i need to know all id parents, node1-node2-node4

there is a function in umbraco.library or some recursive templete to do this??

regards.

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Markus Johansson 1936 posts 5864 karma points MVP 2x c-trib

Mar 02, 2012 @ 07:32

0

Are you talking about something lika a breadcrumb? I think that theres a build in template for that. But something like this:

<xsl:for-each select="$currentPage/ancestor::* [@level > $minCrumbLevel and string(umbracoNaviHide) != '1']">
   <li>
<a href="{umbraco.library:NiceUrl(@id)}">
   <xsl:value-of select="@nodeName"/>
   </a>
</li>
</xsl:for-each>

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Chriztian Steinmeier 2798 posts 8788 karma points MVP 8x admin c-trib

Mar 02, 2012 @ 15:20
1
Hi Cristian,

If you just need the Ids for some reason, you can grab the @path attribute - it contains a "path of Ids" to the selected node, e.g.:
```
If you have this setup:

Home (id:1050)
  Node1 (id:1052)
    Node2 (id:1053)
    Node3 (id:1054)
    Node4 (id:1055)

You can try:
<xsl:value-of select="$currentPage/@path" /> 
```
But you don't need the Ids if you just want to access the actual nodes - the ancestor-or-self:: axis will select them for you:
```
<xsl:variable name="nodesInPathToCurrent" select="$currentPage/ancestor-or-self::*[@isDoc]" />
```
/Chriztian
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Cristian 24 posts 45 karma points

Mar 02, 2012 @ 15:39

0

Thanks for you reply! both of you.

@path was the property that i was looking for!

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