xslkey strange behavior - XSLT

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Vishal G.P 62 posts 122 karma points

Mar 28, 2012 @ 10:57

XSL:key strange behavior

XSLT

Hey guys,

i have a couple of NewsItems with a date property...

Now i want to make an archive with all the distinct years below each other.. I made my key as below.

And below that i have my foreach which loops thru all my NewsItems...

The problem here is i have 8 or so newsitems, with all different years (as a test).. also i have one with 2012 in the date... But i get all the other years except for the 2012 one... If i change the year (of the date property) to another year say 2014, then i see that year appear in the list. But once put back to any date in 2012, it refuses to show the distinct 2012 year... All other years appear properly...

I dont think i'm doing anything wrong here... right?

In the last code line, i also tried another for-each procedure of the MUENCHIAN method. But the same behaviour as well.

    <xsl:key name="years" match="NewsItem" use="umbraco.library:FormatDateTime(date,'yyyy')" />

<xsl:for-each select="$currentPage/..//*[generate-id() = generate-id(key('years',umbraco.library:FormatDateTime(date,'yyyy'))[1])]">
          <xsl:sort order="descending" select="umbraco.library:FormatDateTime(date,'yyyy')"/>
          <xsl:variable name="currentYear" select="umbraco.library:FormatDateTime(./date,'yyyy')" />
          <div class="year">
            <p class="year-title">
              <a href="#">
                <xsl:value-of select="umbraco.library:FormatDateTime(./date,'yyyy')"/>
              </a>
            </p>
          </div>
        </xsl:for-each>

<xsl:for-each select="$currentPage/..//*[count(. | key('years',umbraco.library:FormatDateTime(date,'yyyy'))[1]) = 1]">

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Chriztian Steinmeier 2798 posts 8788 karma points MVP 7x admin c-trib

Mar 29, 2012 @ 22:30

Hi Vishal,

You're right, the code looks like it should work... you could try the following snippet, just as a sanity-check:

<xsl:key name="years" match="NewsItem" use="substring(date, 1, 4)" />

<xsl:for-each select="$currentPage/..//*[generate-id() = generate-id(key('years', substring(date, 1, 4))[1])]">
    <xsl:sort select="date" data-type="text" order="descending" />

    <xsl:variable name="currentYear" select="substring(date, 1, 4)" />
    <div class="year">
        <p class="year-title">
            <a href="#">
                <xsl:value-of select="$currentYear" />
            </a>
        </p>
    </div>
</xsl:for-each>

It does the same thing, but without calling any extension functions (not necessary in this case) ... ?

If this gives you the same result, I'd bet there's something fishy with that 2012 node.

/Chriztian

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Vishal G.P 62 posts 122 karma points

Mar 29, 2012 @ 22:48

0

Hi Chriztian,

i tried that code as well yesterday, but still got the same result.. I converted to C# extension method to get the distinct years and that worked :-)

So for now this still remains a puzzle... anywho... thanks for your input..

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