I am looking for a way to display links in a sidebar that display each parent node and its children. It is easy enough to display one set of parents and children, but I am having trouble getting multiples to work. This is the output goal:

<sidebar>

Parent 1
-- child 1
-- child 2
-- child 3

Parent 2
-- child 1
-- child 2
-- child 3

</sidebar>

I have this working part way, thanks to a solution posted by Sune Jepsen and Thijs Kuipers at http://our.umbraco.org/forum/developers/xslt/15660-multi-level-menu, but it doesn't quite do what I want, and I'm having trouble because I haven't worked with xsl:call-template before.

The output of the XSLT below is:

<sidebar>

Parent 1
-- child 1
-- child 2
-- child 3

Parent 2 (without any children beneath it)

</sidebar>

Here is the XSLT I am using: My guess is that something needs to be changed in the nested xsl:choose clauses, but I'm not sure where to go from here.

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet
        version="1.0"
        xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
        xmlns:msxml="urn:schemas-microsoft-com:xslt"
        xmlns:umbraco.library="urn:umbraco.library"
        exclude-result-prefixes="msxml umbraco.library">


<xsl:output method="xml" omit-xml-declaration="yes"/>

  <xsl:param name="currentPage"/>

  <xsl:template match="/">

    <xsl:variable name="subMenuTopLevelNodes" select="$currentPage/ancestor-or-self::* [@level = 2]/* [string(umbracoNaviHide) != '1' and @isDoc]"/>
    <xsl:if test="count($subMenuTopLevelNodes) &gt; 0">
      <h1><xsl:value-of select="$currentPage/../@nodeName" /></h1>
        <nav>
          <xsl:call-template name="submenuTree">
            <xsl:with-param name="pageNodes" select="$subMenuTopLevelNodes"/>
          </xsl:call-template>
        </nav>
    </xsl:if>
  </xsl:template>

  <xsl:template name="submenuTree">
    <xsl:param name="pageNodes"/>
    <xsl:for-each select="$pageNodes">

        <a href="{umbraco.library:NiceUrl(@id)}">
          <xsl:choose>
            <xsl:when test="count(current()/*[string(umbracoNaviHide) != '1' and @isDoc]) &gt; 0">
              <xsl:choose>
                <xsl:when test="$currentPage/@level &gt;= current()/@level and @id = $currentPage/ancestor-or-self::*[@level=current()/@level]/@id">
                  <xsl:attribute name="class">show-children</xsl:attribute>
                  <xsl:if test="$currentPage/@id = @id">
                    <xsl:attribute name="class">show-children selected</xsl:attribute>
                  </xsl:if>
                </xsl:when>
                <xsl:otherwise>
                  <xsl:attribute name="class">has-children</xsl:attribute>
                  <xsl:if test="$currentPage/@id = @id">
                    <xsl:attribute name="class">has-children selected</xsl:attribute>
                  </xsl:if>
                </xsl:otherwise>
              </xsl:choose>
            </xsl:when>
            <xsl:otherwise>
              <xsl:if test="$currentPage/@id = @id">
                <xsl:attribute name="class">selected</xsl:attribute>
              </xsl:if>
            </xsl:otherwise>
          </xsl:choose>
          <xsl:value-of select="@nodeName"/>
        </a>

        <xsl:if test="$currentPage/@level &gt;= current()/@level and @id = $currentPage/ancestor-or-self::*[@level = current()/@level]/@id and count(current()/*[string(umbracoNaviHide) != '1' and @isDoc]) &gt; 0">
            <xsl:call-template name="submenuTree">
              <xsl:with-param name="pageNodes" select="$currentPage/ancestor-or-self::*[@level = current()/@level]/*[string(umbracoNaviHide) != '1' and @isDoc]"/>
            </xsl:call-template>
        </xsl:if>
    </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>

Your assistance is enormously appreciated!