Hi Fuji,

Are you not only sorting by count? (It looks like that to me but it may of course be because you've simplified the problem here).

Anyways, how is the count stored? Is it a property on the documents or do you have to call that extension to get it?

If you need to call the extension, this should work:

<xsl:sort select="ViewCount:GetViews(@id)//@count" data-type="number" order="descending" />

Could you post the XML you get from a call to ViewCount:GetViews(@id) ?

/Chriztian

Hi Chriztian,

Yes its a property in the document, and using the Refactored Content Views package to get the number of views a node has been viewed.

Here i need to sort all child nodes displaying the most viewed one. Here is how my code looks like

<xsl:if test="*[@isDoc][not(umbracoNaviHide = 1)]">            
         <xsl:for-each select="./* [@isDoc and string(umbracoNaviHide) !='1']">    
      <xsl:sort select="ViewCount:GetViews(@id)/@count" data-type="number" order="descending" />
           <xsl:variable name="counter" select="ViewCount:GetViews(number(@id))" />    
<li>
           <a href="{umbraco.library:NiceUrl(../@id)}"><xsl:value-of select="../@nodeName"/></a>  <br/> 
           <small><xsl:value-of select="umbraco.library:FormatDateTime(../@createDate, 'dd MMMM yyyy')" /></small><br/>
           <small style="color:#000;">Number of views : <xsl:value-of select="$counter//@count" /></small>
             <br/>   
             <a href="{umbraco.library:NiceUrl(../@id)}" class="rd">view more &#187; </a>
           </li>           
        </xsl:for-each>      
      </xsl:if>

You will notice am displaying the parent name thought instead of the Child. Unfortunately the sorting is still not working. I also tried but without any success

<xsl:sort select="ViewCount:GetViews(number(@id))//@count" order="descending"  data-type="number"  />

Chriztian,

Sorry the sorting is working but what i would like is sorting all child nodes depending on the Count regardless of the parent. Right now the sorting is working as such 

- FOLDER
-- Vids AB
 --Vids 3(count 10)
--Vids 4(count 16)
-- Vids BC
-- Vids 2 (count 3)
      -- Vids 6(count 5)
-- Vids BC
-- Vids 1(count 12)

Output right now when using  is 

• Vids 4 (count 16)
• Vids 3 (count 10)
• Vids 6 (count 5)
• Vids 2 (count 3)
• Vids 1 (count 12)

 <xsl:sort select="ViewCount:GetViews(@id)//@count" order="descending"  data-type="number" />

Expected output

• Vids 4 (count 16)
• Vids 1 (count 12)
• Vids 3 (count 10)
• Vids 6 (count 5)
• Vids 2 (count 3)

Any suggestions on this please?? Getting the impression that this is not possible because of each Parent Node. Am i right on this or is there a way od achiving the sorting?

Hi Chriztian,

Thanks for the help. I guess you changed the way i see xslt again!! My error was in my loop, changing it so check all DocType made it easier.

My previous code 

<xsl:for-each select="umbraco.library:GetXmlNodeById($List)/* [@isDoc][not(umbracoNaviHide != '1')]">
<xsl:if test="*[@isDoc] [not(umbracoNaviHide != '1')] ">             
         <xsl:for-each select="./* [@isDoc ][not(umbracoNaviHide) !='1']">   
<xsl:sort select="ViewCount:GetViews(@id)//@count" order="descending"  data-type="number" />
           <xsl:variable name="counter" select="ViewCount:GetViews(number(@id))" /> 
            <xsl:value-of select="../@nodeName" />     
<xsl:value-of select="$counter//@count" /> 
 </xsl:for-each>        
      </xsl:if> 
</xsl:for-each>  

Working one

<xsl:variable name="folder" select="umbraco.library:GetXmlNodeById($List)" />  
<xsl:for-each select="$folder//DocTypeAlias[not(umbracoNaviHide != '1')]">
......
 </xsl:for-each>

Thanks for the help 
//Fuji 

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