xslt menu problem newbie - XSLT

ben 18 posts 38 karma points

Aug 07, 2009 @ 00:17

XSLT Menu Problem - Newbie!

Hello there, I am running the latest Umbraco 4.0.2.1 on windows xp, .NET 3.5.

I have a menu, where by there are top level menu items and some of these pages can have children, and i only want to show these children if the parent page is selected, but i cant get the if condition to work properly here is my xslt:

At the moment it does get out the children for the page that has children but when clicking on any other page it renders the rest of the top level pages as sub level ones, i am very new to umbraco and xslt!

Please help!

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [
    <!ENTITY nbsp "&#x00A0;">
]>
<xsl:stylesheet
  version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:umbraco.library="urn:umbraco.library"
   exclude-result-prefixes="msxml umbraco.library">


    <xsl:output method="xml" omit-xml-declaration="yes"/>

    <xsl:param name="currentPage"/>

    <xsl:template match="/">

        <ul id="navi">

            <xsl:variable name="rootNode" select="$currentPage/ancestor-or-self::node [@level=1]" />
         
          <xsl:variable name="rootTextpageNode" select="$currentPage/ancestor-or-self::node [@level = 2 and @nodeTypeAlias = 'MainPage']" />
            
            <li>
                           
                <a href="{umbraco.library:NiceUrl($rootNode/@id)}">
        <!--
                    Add the class selected if the root node ID matches our 
                    current node ID in the for each loop
                    -->
                <xsl:if test="$rootNode/@id = $currentPage/@id">
                    <xsl:attribute name="class">
                        <xsl:text>
                            on
                        </xsl:text>
                    </xsl:attribute>
                </xsl:if>
                    <xsl:value-of select="$rootNode/@nodeName" />
                </a>
             
            </li>
         
          
            
            <xsl:for-each select="$currentPage/ancestor-or-self::node/node [@level = 2 and string(data[@alias='umbracoNaviHide']) != '1']">
                <li>
                         
              <xsl:if test="@nodeName = 'Contact'">
                   <xsl:attribute name="class">
                        <xsl:text>
                            contact
                        </xsl:text>
                    </xsl:attribute>
              </xsl:if>    
                    <a href="{umbraco.library:NiceUrl(@id)}">
          <!--
                    Add the class selected if the currentpage or parent nodes (up the tree to the root) 
                    ID matches our current node ID in the for each loop
                    -->
                    <xsl:if test="$currentPage/ancestor-or-self::node/@id = current()/@id">
                        <xsl:attribute name="class">
                            <xsl:text>
                                on
                            </xsl:text>
                        </xsl:attribute>
                    </xsl:if>
                        <xsl:value-of select="@nodeName" />  
                      
                    </a>
                  <xsl:if test="$rootTextpageNode/@id = current()/@id">
                   <ul>
                        <xsl:for-each select="$rootTextpageNode/node">
                          <li>
                                <a href="{umbraco.library:NiceUrl(current()/@id)}">
                                 <xsl:if test="$currentPage/ancestor-or-self::node/@id = current()/@id">
                                     <xsl:attribute name="class">
                                            <xsl:text>on</xsl:text>
                                       </xsl:attribute>
                                    </xsl:if>
                                   <span>
                                      <xsl:value-of select="current()/@nodeName"/>
                                    </span>
                             </a>
                            </li>
                       </xsl:for-each>       
                  </ul>
                   </xsl:if>
                </li>
              
            </xsl:for-each>
           
        </ul>

    </xsl:template>

</xsl:stylesheet>

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XSLT Menu Problem - Newbie!