prceeding following siblings from media library id - XSLT

Jamie 35 posts 87 karma points

Oct 07, 2012 @ 08:53

Prceeding - Following Siblings from Media Library ID

XSLT

I'm passing an Media folder ID via a Query string and want to print out a list of the sibling folders with links for a menu.

I can see that thecode

            <textarea>
                <xsl:copy-of select="$folder"/> 
            </textarea>

Gives me an XML result and I can loop that out in another XSLT file to show the images.. but for the life of me I can't get the sibling links to be shown .. have spent about 4 hours trying different variations to following-sibling / preceding-sibling syntax to get nothing. The code below looks to me like it should work but I get nothing other then the current folder name displayed.

        <xsl:param name="currentPage" />
        <xsl:param name="mediafolder" select="umbraco.library:RequestQueryString('gallery')" />

        <xsl:template match="/">
                                        
        <xsl:if test="$mediafolder !=''">
                
            <xsl:variable name="folder" select="umbraco.library:GetMedia($mediafolder, true())" />    
            
            <textarea>
                <xsl:copy-of select="$folder"/> !contentToKeepEmptyXMLVisible!
            </textarea>
                
            <xsl:if test="$folder != ''">

                <ul>
                <xsl:for-each select="$folder/preceding-sibling::*[@nodeTypeAlias = 'Folder']">
                    
                    <li>x
                        <a href="?gallery={./@id}" class="external">
                            <xsl:value-of select="./@nodeName" />                            
                        </a>
                    </li>
                </xsl:for-each>
                    
                <li class="selected"><xsl:value-of select="$folder/@nodeName" /></li>

                <xsl:for-each select="$folder/following-sibling::*[@nodeTypeAlias = 'Folder']">
                    
                    <li>
                        <a href="?gallery={./@id}" class="external">
                            <xsl:value-of select="./@nodeName" />                            
                        </a>
                    </li>
                </xsl:for-each>
                    
                </ul>
            </xsl:if>
                    
        </xsl:if>
            
        </xsl:template>

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Chriztian Steinmeier 2798 posts 8788 karma points MVP 7x admin c-trib

Oct 07, 2012 @ 12:42

Hi Jamie,

The reason you can't access the siblings is that they're not present in the XML you get from GetMedia() - you only get the folder you ask for with its descendants.

You need to grab the parent folder instead, e.g.:

<xsl:param name="currentPage" />
<xsl:param name="mediafolder" select="umbraco.library:RequestQueryString('gallery')" />
<xsl:param name="galleriesFolder" select="umbraco.library:GetMedia(PARENT_FOLDER_ID, true())" />

<xsl:template match="/">
    <xsl:if test="normalize-space($mediafolder)">
        <xsl:variable name="folder" select="$galleriesFolder/*[@nodeTypeAlias = 'Folder'][@id = $mediafolder]" />
        <xsl:if test="$folder">
            <ul>
                <xsl:apply-templates select="$folder/*[@nodeTypeAlias = 'Folder']" />
            </ul>
        </xsl:if>
    </xsl:if>
</xsl:template>

<xsl:template match="@nodeTypeAlias = 'Folder'">
    <li>
        <xsl:choose>
            <xsl:when test="@id = $mediafolder">
                <xsl:attribute name="class">selected</xsl:attribute>
                <xsl:value-of select="@nodeName" />
            </xsl:when>
            <xsl:otherwise>
                <a href="?gallery={@id}" class="external">
                    <xsl:value-of select="@nodeName" />
                </a>
            </xsl:otherwise>
        </xsl:choose>
    </li>
</xsl:template>

/Chriztian

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Jamie 35 posts 87 karma points

Oct 07, 2012 @ 14:14

Thanks Chriztian,

I did think about going via the parent node .. but I kind of figured the sibling functions would basically do that sort of step for me, and I couldn't see any references anywhere that confilected with what I was trying to do.

The other reason is that generally multiple templates do my head in more then just general XSLT.
For example I copied and pasted (yep lazy gettign you to do all my work) your code above and it gives this error.

"Expected end of the expression, found '='. @nodeTypeAlias -->=<-- 'Folder' "

and I'm not sure what that means. as the line I think it reffrers to looks syntaticaly correct to my eyes.

<xsl:template match="@nodeTypeAlias = 'Folder'">

Jamie

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Chriztian Steinmeier 2798 posts 8788 karma points MVP 7x admin c-trib

Oct 07, 2012 @ 21:58

Hi Jamie,

Arg, sorry about that - bad error on my part. It should read like this:

<xsl:template match="*[@nodeTypeAlias = 'Folder']">

Regarding "multiple templates" in XSLT - I did a presentation on this at Codegarden '10 called "XSLT beyond <for-each>", which demonstrates how that works ... should be able to find it on stream.umbraco.org

/Chriztian

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Prceeding - Following Siblings from Media Library ID