Hi all,

I look after a site that advetisers jobs, the jobs have been created by using the same method of adding a news item as there are never going to be that many jobs. So in the content tab I have a jobs directory and under that are all the jobs.

The company now want the job information displayed in an rss feed, I have created the rss xslt file and can get the content pullled through but as there are quite a few values like job title, salary, employer, details I want to display these in the rss feed.

I have updated this:

<content:encoded>
    <xsl:value-of select="concat('&lt;![CDATA[ ', ./jobTitle,']]&gt;')" disable-output-escaping="yes"/>
</content:encoded>

and say I want to add another value like job details how do I add this as if I just create a new xsl: value like below:

<content:encoded>

<xsl:value-of select="concat('&lt;![CDATA[ ', ./jobTitle,']]&gt;')" disable-output-escaping="yes"/>
<xsl:value-of select="concat('&lt;![CDATA[ ', ./jobDetails,']]&gt;')" disable-output-escaping="yes"/>

</content:encoded>

The output is on one line, how to I get it to go onto it's own line.

Thanks for any help

Lee