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  • yumin 51 posts 243 karma points
    Dec 25, 2012 @ 03:44
    yumin
    0

    XPathException:has an invalid token

    I want to get paging record  from .NET usercontrol. This is my code but I get exception 

    System.Xml.XPath.XPathException: 'descendant::node()[@id='1349']/child::node()[position() >= 0 and position() <= 5]' has an invalid token.

     

    string xPath="descendant::node()[@id='1349']/child::node()[position() >= 0 and position() <= 5]";

    List<Node> nodes = new List<Node>();

    XPathNavigator xPathNavigator = umbraco.content.Instance.XmlContent.CreateNavigator();
    XPathNodeIterator xPathNodeIterator = xPathNavigator.Select(xPath);
    Node node;
    while (xPathNodeIterator.MoveNext())
    {
    node = UmbracoHelper.GetNode(xPathNodeIterator.Current.Evaluate("string(@id)").ToString());
    if (node != null) { nodes.Add(node); }
    }

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  • yumin 51 posts 243 karma points
    Dec 25, 2012 @ 03:49
    yumin
    0

    I created a test.xslt in .net , The strange thing is there is no error with the same code

    <?xml version="1.0" encoding="utf-8"?>

    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"

        xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"

    >

        <xsl:output method="xml" indent="yes"/>

        <xsl:template match="/">

          <xsl:value-of select="descendant::node()[@id='1349']/child::* [position() &gt;= 0 and position() &lt;= 5]"/>

        </xsl:template>

    </xsl:stylesheet>

     I can't figure out what is wrong in my code, any ideas!  Thanks in advace
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  • Jan Skovgaard 11280 posts 23678 karma points MVP 11x admin c-trib
    Dec 26, 2012 @ 16:11
    Jan Skovgaard
    0

    Hi Yumin

    What version of Umbraco are you using?

    /Jan

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  • yumin 51 posts 243 karma points
    Dec 27, 2012 @ 03:43
    yumin
    0

    hi Jan Skovqaard

    Umbraco.4.10.0

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  • Dennis Aaen 4500 posts 18255 karma points admin hq c-trib
    Dec 27, 2012 @ 10:35
    Dennis Aaen
    0

    Hi Yumin,

    Try something like this, I haven'ttest it myself.

     

    <?xml version="1.0" encoding="utf-8"?>
    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
      xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
        <xsl:output method="xml" indent="yes"/>
        <xsl:template match="/">
          <xsl:value-of select="$currentPage/descendant::*[@isDoc and @id='1349' ]/child::* [position() &gt;= 0 and position() &lt;= 5]"/>
        </xsl:template>
    </xsl:stylesheet>

    I hope this can helps you further.

    /Dennis

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  • yumin 51 posts 243 karma points
    Dec 28, 2012 @ 06:19
    yumin
    100

    hi all,

    thanks very much,I have solved the problem

    xpath expression can not use &gt; and &lt; in .net, Otherwise will get a invalid token exception

    use > and < instead

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