Hi Brian,

If you need a reference to the parent and display the node name, use 

<xsl:value-of select="$currentPage/../@nodeName"/>

or

<xsl:value-of select="$currentPage/parent::node/@nodeName"/>

Also, take a look at this wiki page

Cheers,

/Dirk

Hi Dirk,

I confused my self a bit apparently!

My Macro is really on the News page. And on this page i want to show the parent of the August page - in this example the 2009 page.

Is that possible?

best regards
Brian

Hi Brian,

Show us the complete xslt, so we can get hold of the context. It's quite easy to get the 2009 page from the August page, but it all depends how you get to the August page first? So, willing to share that bit of code?

Cheers,

/Dirk

Hi Dirk,

It's a rather long xslt file. to sum up, i have a structure like this:

news page (My Macro is on this page!)
---- 2009
----- august
---- 2010
----- september

And so on!
On the news page i want to display the nodename of the August, September and all the other months/nodes above an image. This Works. But I would also like to show the correct year = so that it will displat August 2009 and September 2010.

The XSLT is probabably not "best practice" - but it works. Suggetions are appreciated though :)

    <xsl:output method="html" omit-xml-declaration="yes"/>
    <xsl:param name="currentPage"/>
    <xsl:variable name="maxItems" select="/macro/maxItems"/>
    <xsl:param name="MaxNoChars" select="150" />
    <xsl:variable name="level" select="4"/>
    <xsl:template match="/">

<xsl:for-each select="$currentPage/descendant-or-self::node [@level=$level]/node [string(data [@alias='umbracoNaviHide']) != '1']"> 
   <!-- THE IF, WILL TEST HOW MANY ITEMS TO SHOW -->
    <xsl:if test="position() &lt;= $maxItems">
        <h2>
        
<!-- Month - taken from the node name-->
        <xsl:value-of select="@nodeName" disable-output-escaping="yes"/> 

                <!-- Year - taken from the node/folder name-->                

                </h2>
               <!-- THE PHOTO OF THE NEWS MAGAZINE -->
            <xsl:variable name="englishfile" select="umbraco.library:GetMedia(number(./data[@alias='BWnewsFile']),'false')"/>
                <a href="{$englishfile/data[@alias='umbracoFile']}">
                <img style="border: none;">
                <xsl:attribute name="src">
                <xsl:value-of select="umbraco.library:GetMedia(data [@alias = 'BWnewsPhoto'], 'false')/data [@alias = 'umbracoFile']"/>
                </xsl:attribute>
                </img>   
            </a>
       
        <br />
        <!-- THE DANISH PDF FILE OF THE NEWS MAGAZINE -->
        <!-- FIRST SHOW THE PDF LOGO FROM THE MEDIA LIBRARY -->
        <img>
        <xsl:attribute name="src">
        <xsl:value-of select="umbraco.library:GetMedia(1497, 'false')/data [@alias = 'umbracoFile']"/>
        </xsl:attribute>
        </img>
        <!-- REMEMBER THE SPACE BETWEEN THE PDF LOGO AND THE LINK -->
        &nbsp;
        <!-- THEN SHOW THE LINK TO THE DANISH FILE -->
        <xsl:variable name="danishfile" select="umbraco.library:GetMedia(number(./data[@alias='BWnewsFileDanish']),'false')"/>
                <a href="{$danishfile/data[@alias='umbracoFile']}">In danish</a>
</xsl:if>   
</xsl:for-each

Best regards,

Brian

Hi Nico!

Thanks a bunch. Simple, simple, simple.

best regards
Brian

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