<?xml version="1.0" encoding="utf-8" ?>
<xsl:stylesheet
    version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:umb="urn:umbraco.library"
    exclude-result-prefixes="umb"
>

    <xsl:output method="xml" indent="yes" omit-xml-declaration="yes" />

    <xsl:param name="currentPage" />

    <!-- Use the name of the parent DictionaryItem here -->
    <xsl:variable name="labels" select="umb:GetDictionaryItems('PARENT_KEY')/DictionaryItems/DictionaryItem" />

    <xsl:template match="/">
        <ul class="Btn">
            <li><a href="en.aspx"><xsl:value-of select="$labels[@key = 'main nav']" /></a></li>
            <li><a href="sgoiltean.aspx"><xsl:value-of select="$labels[@key = 'button 2']" /></a></li>
            <li>
                <a href="#"><xsl:value-of select="$labels[@key = 'button 3']" /></a>
                <div>
                    <ul>
                        <li><a href="bhidiothan.aspx"><xsl:value-of select="$labels[@key = 'button 4']" /></a></li>
                        <li><a href="bilinguaslism-matters.aspx"><xsl:value-of select="$labels[@key = 'button 5']" /></a></li>
                        <li><a href="rannsachadh.aspx"><xsl:value-of select="$labels[@key = 'button 6']" /></a></li>
                        <li><a href="fios-is-freagairt.aspx"><xsl:value-of select="$labels[@key = 'button 7']" /></a></li>
                        <li><a href="tesisteanasan.aspx"><xsl:value-of select="$labels[@key = 'button 9']" /></a></li>
                        <li><a href="cothroman-cosnaidh.aspx"><xsl:value-of select="$labels[@key = 'button 8']" /></a></li>
                    </ul>
                </div>
            </li>
            <li><a href="ceistean.aspx"><xsl:value-of select="$labels[@key = 'button 10']" /></a></li>
            <li><a href="ceanglaichean.aspx"><xsl:value-of select="$labels[@key = 'button 11']" /></a></li>
        </ul>
    </xsl:template>

</xsl:stylesheet>

Thanks Chriztian

I've just started working with Umbraco this week. Here's the website structure within the contents section.

I'm creating a multilingual site.

Rather than hard coding the URL within the XSLT is there a way of getting the link to the parent page.

Hi Malick,

Yes - there's lots of ways to do this dynamically. I suggest you check out the default templates that ships with Umbraco (Developer > right-click XSLT folder and create a new file - choose "List Subpage by Level" and see how that's constructed). They show how to get the URL of a page, and it's name etc.

Then come back here with any questions you have from looking into that.

/Chriztian

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