umbraco macro xslt not working

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Mehtab Malik 21 posts 70 karma points

Jul 07, 2013 @ 10:09

get an image folder parameter (folder present in the media section) from macro in Umbraco and then loop through the all the images. First thing I check that folder is not empty and then during the loop I further try to check if an image name is equal to "marhall_spadayhpbanner_jul131%20(4).jpg" then I need to put a different link to anchor. I have tried the following xslt code but for some reason its not working as expected and the second condition (when image equal to 'media/42595/marhall_spadayhpbanner_jul131%20(4).jpg' ) is never true.

<xsl:for-each select="$imageFolderContents/node [@nodeTypeAlias='Image']">
    <xsl:if test="string(current()/data [@alias='umbracoFile']) != ''">
        <a href="www.somelink.com">
            <img alt="{current()/@nodeName}">
                <xsl:attribute name="src"><xsl:value-of select="current()/data [@alias='umbracoFile']"/></xsl:attribute>
            </img>
        </a>
    </xsl:if>
    <xsl:if test="string(current()/data [@alias='umbracoFile']) = 'media/42595/marhall_spadayhpbanner_jul131%20(4).jpg'">
        <a href="someotherlink.com">
            <img alt="{current()/@nodeName}">
                <xsl:attribute name="src"><xsl:value-of select="current()/data [@alias='umbracoFile']"/></xsl:attribute>
            </img>
        </a>
    </xsl:if>
</xsl:for-each>

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Jan Skovgaard 11280 posts 23678 karma points MVP 11x admin c-trib

Jul 07, 2013 @ 10:55

0

Hi Methab

What version of Umbraco are you using? The above example is using the old XML schema, which was changed in Umbraco 4.5 so if you're using a newer version of Umbraco that's why the above does not work and we need to refactor it.

/Jan

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Mehtab Malik 21 posts 70 karma points

Jul 07, 2013 @ 11:35

0

thanks for the reply Jan. I m using and old version of umbraco 4.0.3.

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Chriztian Steinmeier 2800 posts 8790 karma points MVP 8x admin c-trib

Jul 08, 2013 @ 01:21

Hi Mehtab,

It probably didn't work because the umbracoFile property will output an absolute path (starting with a slash).

You should be able to just do this - I assumed you didn't want the link + image twice, in case of a match:

<xsl:for-each select="$imageFolderContents/node[@nodeTypeAlias = 'Image']">
    <xsl:variable name="filePath" select="data[@alias = 'umbracoFile']" />
    <xsl:if test="normalize-space($filePath)">
        <a href="http://www.somelink.com">
            <!-- Change the link if this is a specific file -->
            <xsl:if test="$filePath = '/media/42595/marhall_spadayhpbanner_jul131%20(4).jpg'">
                <xsl:attribute name="href">http://www.someothersite.com</xsl:attribute>;
            </xsl:if>
            <img src="{$filePath}" alt="@nodeName}" />
        </a>
    </xsl:if>
</xsl:for-each>

/Chriztian

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