only show content if tags 0 - XSLT

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Gary 40 posts 129 karma points

Aug 02, 2013 @ 11:57

Only show content if tags > 0

Hello,

I have a group of tags sitting in a styled div using this code

<xsl:if test="($currentPage/descendant-or-self::*/parent::*[@isDoc and @parentID='4253'])">
    <div class="ssnSubNode"><strong>Tag Group Title</strong></div>
    <ul>
        <xsl:for-each select="tagsLib:getAllTagsInGroup('tagGroup1')//tag">
            <li style="padding:7px 0 0 10px;"><a href="?tag={.}"><xsl:value-of select="."/></a> (<xsl:value-of select="@nodesTagged"/>)</li>
        </xsl:for-each>
    </ul><br />
</xsl:if>

Can anyone give me guidance on how i can hide all of the above if there is no tags?

Many thanks,

Gary

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Dennis Aaen 4500 posts 18255 karma points admin hq c-trib

Aug 02, 2013 @ 12:14

Hi Gary,

I must say this is a shot in the dark because I don´t have worked with the tagsLib:getAllTagsInGroup before, but I want to try to help you anyway.

<xsl:iftest="$currentPage/descendant-or-self::*/parent::*[@isDoc and @parentID='4253'])">
    <xsl:iftest="count(tagsLib:getAllTagsInGroup('tagGroup1')//tag) > 0">

    <divclass="ssnSubNode"><strong>Tag Group Title</strong></div>
    <ul>
        <xsl:for-eachselect="tagsLib:getAllTagsInGroup('tagGroup1')//tag">
            <listyle="padding:7px0010px;">
              <ahref="?tag={.}"><xsl:value-ofselect="."/></a> (<xsl:value-of select="@nodesTagged"/)          
            </li>
        </xsl:for-each>
    </ul><br/>
</xsl:if>
  </xsl:if>

But as I said it´s a shoot in the dark.

/Dennis

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Gary 40 posts 129 karma points

Aug 02, 2013 @ 12:55

0

Dennis, you are a star! Thank you so much this worked like a charm!!

Much appreciated.

Gary

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