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  • SaphuA 124 posts 87 karma points
    Oct 14, 2009 @ 12:54
    SaphuA
    0

    Sorting

    Hello,

    I have the following xslt that spits out some xml:

    <xsl:for-each select="$parent/node [string(./data [@alias='umbracoNaviHide']) != '1']">
        <xsl:sort select="@sortOrder" />
        ...
    </xsl:for-each>

    However, the created items are not in the same order as in the Umbraco Content view.
    Am I doing something wrong?

    Thanks!

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  • Roger Hughes 55 posts 88 karma points
    Oct 14, 2009 @ 13:17
    Roger Hughes
    0

    Hi, try something like:

    <xsl:sort select="@sortOrder" order="descending"/>

    <xsl:sort select="@sortOrder" order="ascending"/>

     

    Rog ;-)

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  • SaphuA 124 posts 87 karma points
    Oct 14, 2009 @ 13:34
    SaphuA
    0

    Thanks for your reply, but that didn't work. I think "ascending" is the default value anyway.

    I'm starting to think that this is a bug in umbraco. Because when I use descending, I get the same scrambled order, but reversed. I've tried republishing every node, but without succes.

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  • Douglas Robar 3570 posts 4711 karma points MVP ∞ admin c-trib
    Oct 14, 2009 @ 13:37
    Douglas Robar
    0

    What version of umbraco are you using? There was a bug with really long node names in one of the v3 versions.

    cheers,
    doug.

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  • SaphuA 124 posts 87 karma points
    Oct 14, 2009 @ 13:44
    SaphuA
    0

    v4.0.2.1

    I think I've figured it out! Here's the result of the sorting:

    0 1 10 11 12 2 3 4 5 6 7 8 9

    It appears it's sorting it as a string and not as an int. I suck at xslt, so I don't know how I can make it treat sortOrder as an int, will get back when I find it.

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  • SaphuA 124 posts 87 karma points
    Oct 14, 2009 @ 13:47
    SaphuA
    0

    Aaaand found it.

    <xsl:sort select="@sortOrder" data-type="number" />

    Thanks for the help everyone!

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  • Roger Hughes 55 posts 88 karma points
    Oct 14, 2009 @ 15:00
    Roger Hughes
    0

    excellent, i'll make a note of that one :-)

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