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  • John Halsey 59 posts 220 karma points
    Feb 24, 2014 @ 15:27
    John Halsey
    0

    How to access the second root node in tree with XSLT

    I have written a small XSLT script to list out banner images. (see code below).

    I have 2 root nodes, one called home, and one called banner.  Our designers want a rolling banner on every page, so figured I would stick the macro in the main template, but also to make it easier, I have put the banner folder, with all the images as a second root node, see image.

    My question is, how to I target just that node in my xslt code?

    <ul>
    <xsl:for-each select="Banner/BannerImage [@isDoc]">
    <xsl:choose>
    <xsl:when test="url != ''">
                    <!-- check to see if the new browser check box was ticked -->
    <xsl:variable name="window">
    <xsl:choose>
    <xsl:when test="linkTarget = 1">
       _blank
    </xsl:when>
    <xsl:otherwise>
       _self
    </xsl:otherwise>
    </xsl:choose>
    </xsl:variable>
                    <!-- did they provide an alt text, if not, use the value in the image name -->
    <xsl:variable name="alt">
    <xsl:choose>
                            <xsl:when test="altText != ''">
                                <xsl:value-of select="altText"/>
                            </xsl:when>
                            <xsl:otherwise>
                                <xsl:value-of select="Name"/>
                            </xsl:otherwise>
    </xsl:choose>
    </xsl:variable>
    <xsl:variable name="mediaImage" select="umbraco.library:GetMedia(bannerImage, false())" />
                    <li>
                        <a href="{url}" target="$window">
    <img src="{$mediaImage/umbracoFile}" alt="{$alt}" />
                        </a>
                    </li>
    </xsl:when>
                <xsl:otherwise>
    <xsl:variable name="alt">
    <xsl:choose>
                            <xsl:when test="altText != ''">
                                <xsl:value-of select="altText"/>
                            </xsl:when>
                            <xsl:otherwise>
                                <xsl:value-of select="Name"/>
                            </xsl:otherwise>
    </xsl:choose>
    </xsl:variable>
    <xsl:variable name="mediaImage" select="umbraco.library:GetMedia(bannerImage, false())" />
                    <li>
    <img src="{$mediaImage/umbracoFile}" alt="{$alt}" />
                    </li>
                </xsl:otherwise>
    </xsl:choose>

    </xsl:for-each>

    </ul>

    FYI, the Banner folder has and alias Banner, and each Image node has an alias BannerImage.

    Thank you for any advice.

  • John Halsey 59 posts 220 karma points
    Feb 24, 2014 @ 15:29
    John Halsey
    0

    Should also mention, when I run this, nothing happens.  It renders blank space, so obviously isn't finding the BannerImages.

  • Dennis Aaen 4500 posts 18255 karma points admin hq c-trib
    Feb 24, 2014 @ 15:35
    Dennis Aaen
    0

    Hi John,

    You can use the GetXmlNodeById library method to get the XML from at specific node. You can find the documentation here: http://our.umbraco.org/wiki/reference/umbracolibrary/getxmlnodebyid

    <xsl:value-of select="umbraco.library:GetXmlNodeById(1234)"/>
    <xsl:for-each select="umbraco.library:GetXmlNodeById(1234)/BannerImage[@isDoc]">

    Hope this helps,

    /Dennis

  • John Halsey 59 posts 220 karma points
    Feb 24, 2014 @ 15:54
    John Halsey
    0

    Beautiful. This worked a treat.  

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