Hello,

I am using this xslt to write a list of nodes (A,B,C etc). The nodes that have sub nodes (organisations beginging with A,B,C etc) are linking to the results page - the nodes with no sub nodes produce a dead link.

<xsl:variable name="orgNode" select="umbraco.library:GetXmlNodeById(4257)"/>
<xsl:variable name="templateID" select="4841" />
<xsl:variable name="orgType" select="umbraco.library:Request('type')" />
   

Find organisation alphabetically<br /><br />
<xsl:for-each select="$orgNode/*[@isDoc][@template = $templateID]">
    <xsl:sort select="@nodeName" data-type="text" order="ascending"/>  
    <a href="{umbraco.library:NiceUrl(@id)}?type={$orgType}" style="float:left; margin: 0 20px 10px 0;">   
        <xsl:if test="not(*[@isDoc and contains(portalOrgType,$orgType)])">
            <xsl:attribute name="style">color:#ccc;float:left; margin: 0 20px 10px 0;cursor:text;</xsl:attribute><xsl:attribute name="href">#</xsl:attribute>
        </xsl:if>
        <xsl:value-of select="@nodeName"/>
    </a>
</xsl:for-each>

How can i prouce a 'Show all' link that would list every single sub node on the results page?

Any help greatly appreciated.

Thanks for looking