Hey all,

Another XSLT search related problem i'm experiencing here and could do with some help please.

I have created an xslt pagination and it seems to be working fine when no search parameters are used to filter but the problem I have got is How do I keep the search form parameters in the pagination when moving next and prev?

Hopefully someone can see something here is my code so far..

<xsl:for-each select="$locationNodes[(not(normalize-space($typeNodes))) and (not(normalize-space($capacityNodes)))] | $typeNodes[(not(normalize-space($locationNodes))) and (not(normalize-space($capacityNodes)))] | $capacityNodes[(not(normalize-space($locationNodes))) and (not(normalize-space($typeNodes)))] | $locationNodes[(@id = $typeNodes/@id) and (@id = $capacityNodes/@id)] | $locationNodes[(@id = $capacityNodes/@id) and (not(normalize-space($typeNodes)))] | $locationNodes[(@id = $typeNodes/@id) and (not(normalize-space($capacityNodes)))] | $typeNodes[(@id = $capacityNodes/@id) and (not(normalize-space($locationNodes)))] | $keywordNodes">


                <p class="paging">Pages:
  <xsl:if test="$pageNumber &gt; 1">
                  <a title="Previous" class="arrows" href="?page={$pageNumber -1}">
                                  <xsl:value-of select="$prev" />
                  </a>
  </xsl:if>

  <xsl:call-template name="for.loop">
    <xsl:with-param name="i">1</xsl:with-param>
    <xsl:with-param name="count" select="ceiling($numberOfItems div $itemsPerPage)"></xsl:with-param>
  </xsl:call-template>


  <xsl:if test="(($pageNumber) * $itemsPerPage) &lt; ($numberOfItems)">
    <a title="Next" class="arrows" href="?page={$pageNumber +1}">
                                <xsl:value-of select="$next" /></a>
  </xsl:if>
                </p>

Any help would be awesome and if you need me to post anymore code or explain further then please ask.

Thanks

Paul