If a node exists in the XML then it is published. You could always check if the node exists with something like

<xsl:variable name="nodeId" select="1180"/>
<xsl:if test="count($currentPage/ancestor-or-self::node[@level=1]//node[@id=$nodeId]) > 0">
</xsl:if>

or

<xsl:variable name="nodeId" select="1180"/>
<xsl:if test="count(umbraco.library:GetXmlNodeById($nodeId)) > 0">
</xsl:if>

XSLT *only* has access to published nodes, so when you request a node id that is now unpublished it will either give an error or fail silently. My guess is that you have a for-each loop on all of the node id's. You'll just want to check that each nodeid actually has some content in it... which means it is currently published.

I can think of a couple ways to do this. One would be to check a propertie's content, such as bodyText. Another would be to get the NiceUrl(). Another would be to do a GetXmlNodeById(). I'm sure there are others.

The important thing is to check the result with the string() != '' syntax one see's everywhere. This will ensure the macro doesn't give an error if the node isn't published.

Shout if you need a code sample.

cheers,
doug.

OR

<xsl:if test="string-length(umbraco.library:GetXmlNodeById('1088')/error) &gt; 0">
Error
</xsl:if>

:-)

Thanks. I'll try out your examples in one of the days :)

I had the same problem I've tried Chris' example and it seems not to work for what I was doing. eg

<xsl:if test="count(umbraco.library:GetXmlNodeById($nodeId)) > 0">

This seems to be because GetXmlNodeById() will return something like "The is no published content for node xxx" so the count will be 1 regardless.

I did not try Ronnie's method though as I just modified the above to test

<xsl:if test="umbraco.library:GetXmlNodeById(./@link)/data [@alias='yourAlias'] != ''>

instead as I was also looking to see if the property was empty even if it was published (I am using the related links datatype and needed to check if content was available on the linked pages). This does work.

Hope it helps :)

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