what syntax do i need to get my nodes in custom xml - XSLT

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Bex 444 posts 555 karma points

Jun 10, 2014 @ 11:10
0

what syntax do I need to get my nodes in custom xml?

XSLT
Hi

I am trying to generate a custom site map that contains custom pages not stored in umbraco. I have xml with a structure like this:
```
<pages>
  <page>
   <id>1</id>
   <name>name 1</name>
   <friendlyurl>http://www.website.com?pages=1</friendlyurl>;
  </page>
  <page>
   <id>2</id>
   <name>name 2</name>
   <friendlyurl>http://www.website.com?pages=2</friendlyurl>;
  </page>
```
this is xml generated in c# and accessed via an extension. I need to loop the pages and create my site map.

So far I have this XSLT
```
<xsl:for-each select="CustomExt:GetCustomPages()">
      <url>
      <loc>            
        <xsl:value-of select="@FriendlyUrl" />
      </loc>
      <lastmod>
       //get later
      </lastmod>
      <changefreq>
        weekly
      </changefreq>
      <priority>
        0.5
      </priority>
    </url>    
</xsl:for-each>
```
What do I need to have in my selects to actually get the friendlyurl? I have tried doing a different select in the for each
```
<xsl:for-each select="CustomExt:GetCustomPages()/pages/page">
```
or <xsl:value-of select="@page" />

I know my syntax is wrong, but I cant work out what syntax I need!

can anyone help?

Bex
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Chriztian Steinmeier 2798 posts 8788 karma points MVP 7x admin c-trib

Jun 10, 2014 @ 11:23
0
Hi Bex,

How does your C# extension return the document? Usually an extension returns something like this:
```
return xmldoc.Select("/");
```
and then you need to do this in the XSLT:
```
<xsl:variable name="pages" select="CustomExt:GetCustomPages()/pages" />

<xsl:for-each select="$pages/page">
    <url>
  <loc>            
    <xsl:value-of select="friendlyurl" />
  </loc>
  <lastmod>
   //get later
  </lastmod>
  <changefreq>
    weekly
  </changefreq>
  <priority>
    0.5
  </priority>
</url>
</xsl:for-each>
```
Hope that helps - basically, the root node of your document is the slash and below that the root element (i.e. your <pages> element).

You select the elements by using the name they have in the XML - which is case-sensitive, by the way.

/Chriztian
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Bex 444 posts 555 karma points

Jun 10, 2014 @ 11:29
0
Hi Chriztian

Thanks for the quick respons!

I am returning it as an XPathNavigator. When I do a
```
<xsl:copy-of select="CustomExt:GetCustomPages()"/>
```
I see all my xml but am I returning the wrong type?

I can return a nodelist by doing
```
doc.SelectNodes("/") 
```
as its an XmlDocument, would this be better?
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Bex 444 posts 555 karma points

Jun 10, 2014 @ 11:46

0

I have tried returning the nodelist but its not a valid type! I have also tried returning a string but that so far isn't working.

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Chriztian Steinmeier 2798 posts 8788 karma points MVP 7x admin c-trib

Jun 10, 2014 @ 13:08
100
Hi Bex,

XPathNavigator should be fine - I think you're just experiencing case-issues...

Are you doing the copy-of inside the XSLT Visualizer in Umbraco? If so, you need to wrap it inside a <textarea> because the visualizer lowercases everything, e.g.:
```
<textarea cols="50" rows="20">
    <xsl:copy-of select="CustomExt:GetCustomPages()" />
</textarea>
```
XML is case-sensitive (and thus XSLT is too) so you need to use the correct casing when referring to the elements in the XML.

/Chriztian
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Bex 444 posts 555 karma points

Jun 10, 2014 @ 13:42

0

..and that's what the problem was! :) thank you!

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what syntax do I need to get my nodes in custom xml?