Hi,

I'm trying to combine the xslt approaches used in this post and this post, to print out prev/next links (but if I'm on the first item, not prev, and if I'm on the last, no next).

The docType structure has "Program" docTypes and underneath those, there are 3 levels of docType 'systemDateFolder' (year->month->day), and finally at the leaf level, "show" docType. I want prev/next on my show items.

The default ordering of the nodes seems to be by createDate, but I am running into instances where this is causing problems. So I need to sort on 'displayDate'. I'm most familiar with sorting inside for-loops like this:

<xsl:sort select="umbraco.library:FormatDateTime(displayDate, 'yyyyMMddHHmm')" data-type="number" order="descending" /> 

But I have eventually found that I cannot sort my set like this when using msxml:nodeset.

So I kind of have it working using the way I would normally do it, but I want to make it closer to the examples in the links above:

<xsl:output method="xml" omit-xml-declaration="yes"/>

<xsl:param name="currentPage"/>

    <!-- root comprising node set --> 
    <xsl:variable name="programRoot" select="$currentPage/ancestor-or-self::cprProgramItem" />

    <!-- Create a special collection of nodes for paging -->
    <xsl:variable name="data" select="msxml:node-set($programRoot/systemDateFolder/systemDateFolder/systemDateFolder/show)" />


<xsl:template match="/">

<xsl:variable name="p">
<xsl:for-each select="$data">
<xsl:if test="$currentPage/@id = ./@id">
<xsl:value-of select="position()" />
</xsl:if>
</xsl:for-each>
</xsl:variable>


        <xsl:variable name="prevNodeId">
            <xsl:choose>
                <xsl:when test="$currentPage/@id = $data[1]/@id">
            <xsl:value-of select="'0'"/>
                </xsl:when>
                <xsl:otherwise>
                    <xsl:value-of select="$data[$p - 1]/@id" />
                </xsl:otherwise>
            </xsl:choose>
        </xsl:variable>

        <xsl:variable name="nextNodeId">
            <xsl:choose>
                <xsl:when test="$currentPage/@id = $data[last()]/@id">
            <xsl:value-of select="'0'"/>
                </xsl:when>
                <xsl:otherwise>
                    <xsl:value-of select="$data[$p + 1]/@id" />
                </xsl:otherwise>
            </xsl:choose>
        </xsl:variable>




<xsl:if test="$prevNodeId != '0'">
<h3 style="background-color:#e4e1e0;padding:.5em .7em;float:left;display:inline;border: 1px solid #ccc;">
<a>
<xsl:attribute name="href">
<xsl:value-of select="umbraco.library:NiceUrl($prevNodeId)" />
</xsl:attribute> OLDER SHOW
</a>
</h3>
</xsl:if>

<xsl:if test="$nextNodeId != '0'">
<h3 style="background-color:#e4e1e0;padding:.5em .7em;float:right;display:inline;border: 1px solid #ccc;">
<a>
<xsl:attribute name="href">
<xsl:value-of select="umbraco.library:NiceUrl($nextNodeId)" />
</xsl:attribute>NEWER SHOW
</a>
</h3>
</xsl:if>


</xsl:template>

I would really like to try and not use loops, and use apply-templates, but I'm getting stuck in a couple of places. Here's what I've got:

    <xsl:output method="xml" omit-xml-declaration="yes"/>

<xsl:param name="currentPage"/>

    <!-- get the parent program root for this show i'm on --> 
    <xsl:variable name="programRoot" select="$currentPage/ancestor-or-self::cprProgramItem" />

    <!-- Use that root to get all the shows. 1) I need to figure out how to sort this using apply-templates I think -->
    <xsl:variable name="data" select="msxml:node-set($programRoot/systemDateFolder/systemDateFolder/systemDateFolder/show)" />





<xsl:template match="/">
<xsl:apply-templates select="$currentPage" />
</xsl:template>

<!-- 2) 'node' here is part of the old schema? I change it to 'show' because those are the alias of the leaves I want to match --> 
    <xsl:template match="show">

       <!-- Find the equivalent of position() but within our special collection -->
<!-- 3) This appears to give me the absolute position of this node in the entire content tree? It's like 2603 on the first item  and there's only 
a couple of hundred of 'shows' in this program. Obviously, I can't use this '$p' to position links from $data. I created a for loop here in order 
    to look up what my currentPage/@id position is inside $data, but I should just get the select syntax right I think? I want to not use loops. 
--> 

        <xsl:variable name="p">
            <xsl:number level="any" count="show" />
        </xsl:variable>

<!-- 
    <xsl:variable name="p">
    <xsl:for-each select="$data">
    <xsl:if test="$currentPage/@id = ./@id">
    <xsl:value-of select="position()" />
    </xsl:if>
    </xsl:for-each>
    </xsl:variable>
--> 

        <xsl:variable name="prevNodeId">
            <xsl:choose>
                <xsl:when test="$currentPage/@id = $data[1]/@id">
            <xsl:value-of select="'0'"/>
                </xsl:when>
                <xsl:otherwise>
                    <xsl:value-of select="$data[$p - 1]/@id" />
                </xsl:otherwise>
            </xsl:choose>
        </xsl:variable>

        <xsl:variable name="nextNodeId">
            <xsl:choose>
                <xsl:when test="$currentPage/@id = $data[last()]/@id">
            <xsl:value-of select="'0'"/>
                </xsl:when>
                <xsl:otherwise>
                    <xsl:value-of select="$data[$p + 1]/@id" />
                </xsl:otherwise>
            </xsl:choose>
        </xsl:variable>


<xsl:if test="$prevNodeId != '0'">
<h3 style="background-color:#e4e1e0;padding:.5em .7em;float:left;display:inline;border: 1px solid #ccc;">
<a>
<xsl:attribute name="href">
<xsl:value-of select="umbraco.library:NiceUrl($prevNodeId)" />
</xsl:attribute> OLDER SHOW
</a>
</h3>
</xsl:if>

<xsl:if test="$nextNodeId != '0'">
<h3 style="background-color:#e4e1e0;padding:.5em .7em;float:right;display:inline;border: 1px solid #ccc;">
<a>
<xsl:attribute name="href">
<xsl:value-of select="umbraco.library:NiceUrl($nextNodeId)" />
</xsl:attribute>NEWER SHOW
</a>
</h3>
</xsl:if>







<textarea>
p:<xsl:value-of select="$p" />
currentPage/id:<xsl:value-of select="$currentPage/@id" />
prevNodeId:<xsl:value-of select="$prevNodeId" />
nextNodeId:<xsl:value-of select="$nextNodeId" />
</textarea>

</xsl:template>

So my questions are in the xslt, but basically:

1) How do I sort $data with another apply-templates while still being able to match to the other apply-templates? 2) When I go to find my position in data in a template match, the old schema example was 'node[@nodeTypeAlias = $groupType]/node'

I tried systemDateFolder/show, systemDateFolder/systemDateFolder/systemDateFolder/show, and other variations, but I think I'm not understanding the context of what I'm trying to select with the count variable:

   <xsl:number level="any" count="node[@nodeTypeAlias = $groupType]/node" />

3) I guess if I can figure out 2), three really works itself out.