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  • Eddie Foreman 215 posts 288 karma points
    Sep 16, 2014 @ 18:33
    Eddie Foreman
    0

    Sort by date with getEverythingWithTags

    Hi All,

    Part of my xslt grabs all of the items with a certain tag. 

    <xsl:variable name="matchedNodes" select="Exslt.Tags:getEverythingWithTags($tags)/root/node" />
    <xsl:for-each select="$matchedNodes">
    <xsl:sort select="publishedDate" order="descending"  />
    <xsl:for-each select="umbraco.library:GetXmlNodeById(@id)">
    <p><xsl:value-of select="umbraco.library:FormatDateTime(publishedDate,'dd MMMM yyyy')" /></p>
    </xsl:for-each>
    </xsl:for-each>

    I've tried to sort them using the normal sort method, but as matchedNodes is a list of ids there is no date to sort.

    Does anyone have an example of sorting with 'getEverythingWithTags'? 

    Thanks,
    Eddie

     

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  • Chriztian Steinmeier 2800 posts 8791 karma points MVP 9x admin c-trib
    Sep 16, 2014 @ 19:37
    Chriztian Steinmeier
    100

    Hi Eddie,

    You should be able to do something like this - the trick is of course to use the actual referenced nodes, which is what we're grabbing with the id() function - it accepts a nodeset (all the @id attributes of the $matchedNodes).

    <xsl:template match="/">
    <xsl:variable name="matchedNodes" select="Exslt.Tags:getEverythingWithTags($tags)/root/node" /> 
    <!--
        Loops only a single node, just to get into the right context.
        (See: https://gist.github.com/greystate/8576730)
    -->
    <xsl:for-each select="$currentPage">
        <xsl:apply-templates select="id($matchedNodes/@id)">
            <xsl:sort select="publishedDate" data-type="text" order="descending" />
        </xsl:apply-templates>
    </xsl:for-each> 
</xsl:template>

<!-- Output template -->
<xsl:template match="*[@isDoc]">
    <p>
        <xsl:value-of select="umbraco.library:FormatDateTime(publishedDate, 'dd MMMM yyyy')" />
    </p>
</xsl:template>

    Let me know if it works - maybe it needs some tuning, coming right out of my head without testing :-)

    /Chriztian

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  • Eddie Foreman 215 posts 288 karma points
    Sep 17, 2014 @ 10:52
    Eddie Foreman
    0

    Hi Chriztian,

    Thanks for the example. The existing xslt has a number of templates used for paging, output etc..

    Below is the part of the code that grabs the tags.

    <xsl:variable name="matchedNodes" select="Exslt.Tags:getEverythingWithTags($tags)/root/node" />
    <xsl:for-each select="$matchedNodes">                        
        <xsl:for-each select="umbraco.library:GetXmlNodeById(@id)">
        <xsl:call-template name="article" />
        </xsl:for-each>
    </xsl:for-each>

    Will see if I can get it working with call-template. Just wanted to check if you knew if it's possible with the call-template approach or if it's only possible with apply-templates.

    Thanks, Eddie

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  • Eddie Foreman 215 posts 288 karma points
    Sep 17, 2014 @ 15:12
    Eddie Foreman
    0

    Hi Chriztian,

    All working now. Used your idea to create a new variable that contained the ids in descending date order. Then tweaked my existing could to use the new variable and display the item.

    <!-- Get all nodes that match the tag -->   
              <xsl:variable name="matchedNodes" select="Exslt.Tags:getEverythingWithTags($tags)/root/node" />

              <!-- Sort matched nodes into date order-->    
              <xsl:variable name="sortedMacthedNodes">
                <xsl:for-each select="$currentPage">
                  <xsl:apply-templates select="id($matchedNodes/@id)">
                    <xsl:sort select="publishedDate" data-type="text" order="descending" />
                  </xsl:apply-templates>
                </xsl:for-each>
              </xsl:variable>

              <!-- Display each node -->    
              <xsl:for-each select="msxsl:node-set($sortedMacthedNodes)/node">
                <xsl:if test="position() &gt; $itemsPerPage * number($pageNumber - 1) and position() &lt;= number($itemsPerPage * number($pageNumber - 1) + $itemsPerPage)">
                  <xsl:for-each select="umbraco.library:GetXmlNodeById(@id)">
                    <xsl:call-template name="article" />
                  </xsl:for-each>
                </xsl:if>
              </xsl:for-each>

    Thanks again for the pointers, Eddie

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