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  • Kristian Frost 18 posts 102 karma points
    Dec 10, 2009 @ 14:19
    Kristian Frost
    0

    Sorting output by date

    Hi all!

    Im making a "News"-page at my website and would like to extract the latest news with xslt, and order them by date. How can I do that?
    I've tried to do like this:

    <xsl:for-each select="umbraco.library:GetXmlNodeById($source)/node [string(data [@alias='umbracoNaviHide']) != '1'] [position() &lt; last() - number($count)]">

    Where $source is my newsarchive and $count is the number of latest news to pull out.

    /Kristian

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  • Sebastiaan Janssen 5061 posts 15544 karma points MVP admin hq
    Dec 10, 2009 @ 14:24
    Sebastiaan Janssen
    0

    The sorting can simply be done by doing an xsl:sort right below your for-each (it has to be the first thing after the for-each statement.

    <xsl:sort select="your_date_property" order="descending"/>
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  • Sebastiaan Janssen 5061 posts 15544 karma points MVP admin hq
    Dec 10, 2009 @ 14:26
    Sebastiaan Janssen
    3

    A full example, the XSLT for a list of my latest blog posts looks like this:

    <xsl:param name="currentPage"/>
<xsl:variable name="numberOfPosts" select="3"/>

<xsl:template match="/">

<xsl:for-each select="$currentPage/ancestor-or-self::node //node[@nodeTypeAlias = 'BlogPost']">
<xsl:sort select="@createDate" order="descending" />
    <xsl:if test="position() = 1">
     <h2>Latest blog posts</h2>
    </xsl:if>
    <xsl:if test="position() &lt;= $numberOfPosts">
        <p><a href="{umbraco.library:NiceUrl(@id)}"><xsl:value-of select="@nodeName"/></a></p>
    </xsl:if>
</xsl:for-each>
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  • Kristian Frost 18 posts 102 karma points
    Dec 10, 2009 @ 14:30
    Kristian Frost
    0

    Thanks Sebastiaan, that solved it :)

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  • siva kumar 120 posts 209 karma points
    Oct 09, 2012 @ 05:57
    siva kumar
    0

    hi all,

    how to get top 10 news by using date and year (without considering date) in razor 

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  • Fuji Kusaka 2203 posts 4220 karma points
    Oct 09, 2012 @ 06:23
    Fuji Kusaka
    0

    Hi Siva,

    You could achieve this by making use of OrderBy and Take. Where you will only display 10 news items and make a sorting out of it.

    for e.g

    foreach(dynamic news in newsFolder.Children.OrderBy("createDate descending").Take(10)){
    @news.Name // here am making use of createDate but you can also add a date picker property
    }
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