exclude page from menu based on document type

trfletch 598 posts 604 karma points

Dec 16, 2009 @ 11:53

Hi,

I have an Umbraco V4 website which has a menu that I want to exclude certain document types from, I have tried the following, the bit in bold and underlined is the bit I have added but I don't think I have done this correctly because it is not working, can an XSLT expert give me some help?

<xsl:variable name="maxLevelForSitemap" select="3"/>
<xsl:template match="/">
<div id="sitemap"> 
<ul class="sf-menu sf-menu-home">
<li><xsl:if test="$currentPage/@id = 1053">
<xsl:attribute name="class">active-menu</xsl:attribute>
</xsl:if><a href="/">Home</a></li>
</ul>
<xsl:call-template name="drawNodes">  
<xsl:with-param name="parent" select="$currentPage/ancestor-or-self::node [@level=1]"/>  
</xsl:call-template>
</div>
</xsl:template>
<xsl:template name="drawNodes">
<xsl:param name="parent"/> 
<xsl:if test="umbraco.library:IsProtected($parent/@id, $parent/@path) = 0 or (umbraco.library:IsProtected($parent/@id, $parent/@path) = 1 and umbraco.library:IsLoggedOn() = 1)">
<ul class="sf-menu"><xsl:for-each select="$parent/node [string(./data [@alias='umbracoNaviHide']) != '1' and @level &lt;= $maxLevelForSitemap]"> 
<li><xsl:if test="$currentPage/ancestor-or-self::node/@id = current()/@id">
  <xsl:attribute name="class">active-menu</xsl:attribute>
  </xsl:if>
<xsl:choose>
<xsl:when test="data [@alias = 'nomenulink'] ='1'">
<a href="#">
<xsl:value-of select="@nodeName"/></a>
</xsl:when>
<xsl:otherwise>
<a href="{umbraco.library:NiceUrl(@id)}">
<xsl:value-of select="@nodeName"/></a>
</xsl:otherwise>
</xsl:choose> 
<xsl:if test="count(./node [string(./data [@alias='nestedmenuHide']) != '1' and @level &lt;= $maxLevelForSitemap]) &gt; 0 and @nodeTypeAlias != 'NewsArticle'">   
<xsl:call-template name="drawNodes">    
<xsl:with-param name="parent" select="."/>    
</xsl:call-template>  
</xsl:if> 
</li>
</xsl:for-each>
</ul>
</xsl:if>
</xsl:template>

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dandrayne 1138 posts 2262 karma points

Dec 16, 2009 @ 17:02

Hi There

Here's an example for the business website started pack, adapted from similar code to yours (sitemap.xslt, probably)

<xsl:for-each select="$parent/node [string(./data [@alias='umbracoNaviHide']) != '1' and @level &lt;= $maxLevelForSitemap and @nodeTypeAlias!='NewsItem' and @nodeTypeAlias!='Event' and @nodeTypeAlias!='DateFolder']">

This would seem to fit right into your for-each above.

Dan

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dandrayne 1138 posts 2262 karma points

Dec 16, 2009 @ 17:12

I had the ocd-esque urge to indent your code, and came across a potential problem in the if-else around the call-template. Basically you want to count and make sure no news articles are included in the count - try the following code (untested)

<xsl:variable name="maxLevelForSitemap" select="3"/>
<xsl:template match="/">
   <div id="sitemap"> 
     <ul class="sf-menu sf-menu-home">
           <li>
                <xsl:if test="$currentPage/@id = 1053">
                 <xsl:attribute name="class">active-menu</xsl:attribute>
               </xsl:if>
               <a href="/">Home</a>
          </li>
       </ul>
       <xsl:call-template name="drawNodes">  
          <xsl:with-param name="parent" select="$currentPage/ancestor-or-self::node [@level=1]"/>  
       </xsl:call-template>
    </div>
</xsl:template>


<xsl:template name="drawNodes">
    <xsl:param name="parent"/> 
 <xsl:if test="umbraco.library:IsProtected($parent/@id, $parent/@path) = 0 or (umbraco.library:IsProtected($parent/@id, $parent/@path) = 1 and umbraco.library:IsLoggedOn() = 1)">
       <ul class="sf-menu">
            <xsl:for-each select="$parent/node [string(./data [@alias='umbracoNaviHide']) != '1' and @level &lt;= $maxLevelForSitemap]"> 
               <li>
                    <xsl:if test="$currentPage/ancestor-or-self::node/@id = current()/@id">
                     <xsl:attribute name="class">active-menu</xsl:attribute>
                   </xsl:if>
   
                  <xsl:choose>
                        <xsl:when test="data [@alias = 'nomenulink'] ='1'">
                         <a href="#">
                                <xsl:value-of select="@nodeName"/>
                          </a>
                        </xsl:when>
                     <xsl:otherwise>
                         <a href="{umbraco.library:NiceUrl(@id)}">
                               <xsl:value-of select="@nodeName"/>
                          </a>
                        </xsl:otherwise>
                    </xsl:choose> 
  
                  <xsl:if test="count(./node [string(./data [@alias='nestedmenuHide']) != '1' and @level &lt;= $maxLevelForSitemap and @nodeTypeAlias != 'NewsArticle']) &gt; 0">
                     <xsl:call-template name="drawNodes">    
                            <xsl:with-param name="parent" select="."/>    
                      </xsl:call-template>  
                  </xsl:if> 
              </li>
           </xsl:for-each>
     </ul>
   </xsl:if>
</xsl:template>

Dan

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trfletch 598 posts 604 karma points

Dec 16, 2009 @ 17:45

Thanks Dan,

That has worked perfectly. I know what I wanted to do and pretty much how I wanted to do it I just didn't know the correct syntax to make it happen!

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Exclude page from menu based on document type