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  • Andraž 45 posts 65 karma points
    Dec 20, 2009 @ 19:20
    Andraž
    0

    How to add subNavi

    Hello,

    i would really like to ask for help with 2nd level for Navigation. I really tried everything (to my acknowledge) but i keep coming back to Navi.xsl from Creative Website Wizard. I added template to my site: http://www.simprisk.com/home.aspx and now i wanna have down-drop menu. So, i would like to ask where to add this in this code:

     

    <xsl:template match="/">

    <ul id="nav">
    <li class="sub">
    <xsl:for-each select="$currentPage/ancestor::root/node [string(./data [@alias='umbracoNaviHide']) != '1']">
        <li>
            <a href="{umbraco.library:NiceUrl(@id)}">
                <xsl:attribute name="title"><xsl:value-of select="@nodeName" /></xsl:attribute>
                <xsl:value-of select="@nodeName" />
            </a>
        </li>
    </xsl:for-each>

    <xsl:for-each select="$currentPage/ancestor-or-self::node [@level=1]/node [string(./data [@alias='umbracoNaviHide']) != '1']">
        <li>
            <a href="{umbraco.library:NiceUrl(@id)}">
                <xsl:attribute name="title"><xsl:value-of select="@nodeName" /></xsl:attribute>
                <xsl:value-of select="@nodeName" />
            </a>
        </li>
    </xsl:for-each>
    </li>
    </ul>


    </xsl:template>

     

    I would really be thankful for any help!

    Thanks, Andraž

  • jonok 297 posts 658 karma points
    Dec 21, 2009 @ 01:25
    jonok
    1

    Hi Andraz, I think I know what you are trying to do, see if this code works for you...

    <?xml version="1.0" encoding="utf-8"?>
    <xsl:stylesheet
        version="1.0"
        xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
        xmlns:msxml="urn:schemas-microsoft-com:xslt"
        xmlns:umbraco.library="urn:umbraco.library"
        exclude-result-prefixes="msxml umbraco.library">

        <xsl:output method="html"/>
        <xsl:param name="currentPage"/>

        <xsl:template match="/">

    <ul id="nav">
    <xsl:for-each select="$currentPage/ancestor::root/node [string(./data [@alias='umbracoNaviHide']) != '1']">
        <li>
            <a href="{umbraco.library:NiceUrl(@id)}">
                <xsl:attribute name="title"><xsl:value-of select="@nodeName" /></xsl:attribute>
                <xsl:value-of select="@nodeName" />
            </a>
        </li>
    </xsl:for-each>

    <xsl:for-each select="$currentPage/ancestor-or-self::node [@level=1]/node [string(./data [@alias='umbracoNaviHide']) != '1']">
        <li>
            <a href="{umbraco.library:NiceUrl(@id)}">
                <xsl:attribute name="title"><xsl:value-of select="@nodeName" /></xsl:attribute>
                <xsl:value-of select="@nodeName" />
            </a>
                        <xsl:call-template name="SecondLevelNodes">
                            <xsl:with-param name="parent" select="."/>
                        </xsl:call-template>
        </li>
    </xsl:for-each>
    </ul>

    </xsl:template>

    <xsl:template name="SecondLevelNodes">
            <xsl:param name="parent"/>
            <xsl:if test="count($parent/node[string(data [@alias='umbracoNaviHide']) != '1' ]) > 0">
                <ul class="second-level">
                    <xsl:for-each select="$parent/node[string(data [@alias='umbracoNaviHide']) != '1' ]">
                        <li>
                        <a href="{umbraco.library:NiceUrl(@id)}">
                            <xsl:value-of select="@nodeName"/>
                        </a>
                        </li>
                    </xsl:for-each>
                </ul>
            </xsl:if>
        </xsl:template>

    </xsl:stylesheet>

  • Andraž 45 posts 65 karma points
    Dec 21, 2009 @ 07:22
    Andraž
    0

    Yes, this does the trick.

    Could you just explain me what does this code do: [string(data [@alias='umbracoNaviHide']) != '1' ]) > 0

    I would really like to thank you for your help!

    I wish some day i could pay you back:)

    Thx

  • Sebastiaan Janssen 5060 posts 15522 karma points MVP admin hq
    Dec 21, 2009 @ 07:29
    Sebastiaan Janssen
    0

    If you create a new property on your document types with the alias of "umbracoNaviHide" (the type is: true/false, let's name it "Hide in navigation?"), then it gets used here. If the checkbox is set to true, then 

    [string(data [@alias='umbracoNaviHide']) = '1']

    So the item should not be shown in the navigation. During the part of the XSLT that you highlighted, it says: get all of the pages under the current page that do NOT have umbracoNaviHide set to true.

  • Andraž 45 posts 65 karma points
    Dec 21, 2009 @ 11:24
    Andraž
    0

    Thanks,

    for your time, i'ts getting clearer and clearer :)

     

  • Andraž 45 posts 65 karma points
    Dec 23, 2009 @ 09:17
    Andraž
    0

    I would have one more question thought

    I added a class "sub" to <li> for ancestor-or-sefl node. Now, in my page: http://www.simprisk.com/ it's doing great for the first two navigation buttons "domov" and "login" and also for the drop-down menu on "o portalu" button, but the this class applies to "o nas" and "kontaktirajte nas". How can i make thic class work only if there exists subnavigation (drop-down) menu. Should I use some if statment?

     

    This is the code:

    <xsl:for-each select="$currentPage/ancestor-or-self::node [@level=1]/node [string(./data [@alias='umbracoNaviHide']) != '1']">
        <li class="sub">
            <a href="{umbraco.library:NiceUrl(@id)}">
                <xsl:attribute name="title"><xsl:value-of select="@nodeName" /></xsl:attribute>
                <xsl:value-of select="@nodeName" />
            </a>
                        <xsl:call-template name="SecondLevelNodes">
                            <xsl:with-param name="parent" select="."/>
                        </xsl:call-template>
        </li>
    </xsl:for-each>

    Tnx,

    Andraž

     

  • jonok 297 posts 658 karma points
    Dec 24, 2009 @ 00:11
    jonok
    0

    Hi Andraz, try this - it has an 'if' statement that checks the child page count and adds the class 'sub' if its > 0.

    <xsl:for-each select="$currentPage/ancestor-or-self::node [@level=1]/node [string(./data [@alias='umbracoNaviHide']) != '1']">
        <li>
            <xsl:if test="count(./node[string(data [@alias='umbracoNaviHide']) != '1' ]) > 0">
                <xsl:attribute name="class">sub</xsl:attribute>
            </xsl:if>
            <a href="{umbraco.library:NiceUrl(@id)}">
                <xsl:attribute name="title"><xsl:value-of select="@nodeName" /></xsl:attribute>
                <xsl:value-of select="@nodeName" />
            </a>
                        <xsl:call-template name="SecondLevelNodes">
                            <xsl:with-param name="parent" select="."/>
                        </xsl:call-template>
        </li>
    </xsl:for-each>

  • Andraž 45 posts 65 karma points
    Dec 27, 2009 @ 16:47
    Andraž
    0

    Thanks, if"statment" does the trick

    by

  • Andraž 45 posts 65 karma points
    Jan 06, 2010 @ 07:09
    Andraž
    0

    I have one more question.

    I now the basic...but not when it comes to "if" statements. In my site: "http://www.simprisk.com/o-portalu.aspx" I have two sub-pages "Pogoji poslovanja" and "Naročnina" and that's OK. But if i click on "Pogoji poslovanja" i want to show all of the sub-pages that are under parent of "Pogoji poslovanja". So i guess i should use the "if" statement. For now all i have is this:

     

    <?xml version="1.0" encoding="UTF-8"?>
    <!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
    <xsl:stylesheet
        version="1.0"
        xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
        xmlns:msxml="urn:schemas-microsoft-com:xslt"
        xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets"
        exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets ">

    <xsl:output method="xml" omit-xml-declaration="yes"/>

    <xsl:param name="currentPage"/>

    <xsl:template match="/">
       
    <xsl:for-each select="$currentPage/child::node">
    <li>
            <a href="{umbraco.library:NiceUrl(@id)}">
                <xsl:value-of select="@nodeName"/>
            </a>
    </li>
    </xsl:for-each>
       
    <xsl:for-each select="$currentPage/following-sibling">
    <li>
            <a href="{umbraco.library:NiceUrl(@id)}">
                <xsl:value-of select="@nodeName"/>
            </a>
    </li>
    </xsl:for-each>

    </xsl:template>

    </xsl:stylesheet>

     

    Bye,

     

    Andraz

  • Sebastiaan Janssen 5060 posts 15522 karma points MVP admin hq
    Jan 06, 2010 @ 07:18
    Sebastiaan Janssen
    0

    Just doing a

    <xsl:for-each select="$currentPage/node">

    should work..

  • jonok 297 posts 658 karma points
    Jan 06, 2010 @ 09:36
    jonok
    0

    Andraz - try this...

    <!-- set the top level parent node into a variable (you may need to change  the @level number depending on the depth of the startNode from the root node) -->
    <xsl:variable name="startNode" select="$currentPage/ancestor-or-self::node [@level='2']"/>

    <!-- display the top level node (there would be a much cleaner way of doing this without a 'for-each' but I cant remember just now) -->
    <xsl:for-each select="$startNode">
    <li>
            <a href="{umbraco.library:NiceUrl(@id)}">
                <xsl:value-of select="@nodeName"/>
            </a>
    </li>
    </xsl:for-each>

    <!-- then loop through the children of the start node -->
    <xsl:for-each select="$startNode/node">
    <li>
            <a href="{umbraco.library:NiceUrl(@id)}">
                <xsl:value-of select="@nodeName"/>
            </a>
    </li>
    </xsl:for-each>

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