list sub categories with more than one main category

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Bent Holz 100 posts 273 karma points

Feb 24, 2016 @ 22:53
0

List sub categories with more than one main category

XSLT

Umbraco 6
I'm trying to create a product catalog that has main categories, sub categories and products...

Sub categories can be under more than one main category and a product can be under more than one sub category.

I have set up a doc type for my sub categories where I have added a data type (Ultimate Picker - CheckBoxList). This let's me choose what main categories a sub category belongs to when I create it.

Now I would like XSLT to list the sub categories...
```
<xsl:for-each select="umbraco.library:GetXmlNodeById($source)/* [@isDoc and string(umbracoNaviHide) != '1'][string(hovedkategori) = '1137']">
    <li>
        <a href="{umbraco.library:NiceUrl(@id)}">
            <xsl:value-of select="@nodeName"/>
        </a>
    </li>
</xsl:for-each>
```
This will show all the sub categories that has the main category (ID 1137) selected... but only that ID. So a sub category that has more than that one main category selected will not show.

How do I get it to show sub categories that among others have the specific main category ID?

/cheers
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Chriztian Steinmeier 2798 posts 8788 karma points MVP 7x admin c-trib

Feb 24, 2016 @ 23:01

Hi Bent,

Try using the Split() extension to get a <value> node for every category in the list - then it's easier to do the comparison:

<xsl:variable name="sourceNode" select="umbraco.library:GetXmlNodeById($source)" />

<xsl:for-each select="$sourceNode/*[@isDoc and not(umbracoNaviHide = 1)][umbraco.library:Split(hovedkategori, ',')/value = 1137]">
    <li>
        <a href="{umbraco.library:NiceUrl(@id)}">
            <xsl:value-of select="@nodeName"/>
        </a>
    </li>
</xsl:for-each>

Hope that helps,

/Chriztian

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Bent Holz 100 posts 273 karma points

Feb 25, 2016 @ 15:35

0

That did the trick!

Thank you so very much!

/Bent

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