simple xslt choose not displaying - XSLT

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Doug Clark 30 posts 52 karma points

Mar 19, 2010 @ 03:57
0

simple xslt choose not displaying

XSLT
This seems simple enough, but I can't seem to understand why this code isn't working.
```
<xsl:choose>
<xsl:when test="@nodeTypeAlias = 'HomePage'">
<li class="menu-gap">&nbsp;</li>
</xsl:when>
<xsl:otherwise>
<li class="menu-gap"><a href="/">home</a></li>
</xsl:otherwise>
</xsl:choose>
```
when I'm on the homepage doc type, it is displaying the code in otherwise. What am I missing?
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Neil Campbell 58 posts 182 karma points

Mar 19, 2010 @ 05:48

0

Hi Doug,
It could be that your @nodeTypeAlias is not actually "HomePage" or you may need to do $currentPage/@nodeTypeAlias (depending if your rendering your code in a for-each loop). First try just printing the @nodeTypeAlias to screen out side the conditional statement i.e. <xsl:value-of select="./@nodeTypeAlias" /> and see what come out, then go from there.

Hope this helps.

Neil

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Kim Andersen 1447 posts 2196 karma points MVP

Mar 19, 2010 @ 08:15
0
Hi Doug

I'd try to put $currentPage in front of your @nodeTypeAlias like this:
```
<xsl:choose>
   <xsl:when test="$currentPage/@nodeTypeAlias = 'HomePage'">
      <li class="menu-gap"> </li>
   </xsl:when>
   <xsl:otherwise>
      <li class="menu-gap"><a href="/">home</a></li>
   </xsl:otherwise>
</xsl:choose>
```
This should work in my head. Try it out, and return with your result :)

/Kim A
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Doug Clark 30 posts 52 karma points

Mar 19, 2010 @ 15:03

0

Thanks Neil and Kim. Both of you were correct. I needed to add $currentPage/.

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Kim Andersen 1447 posts 2196 karma points MVP

Mar 19, 2010 @ 20:32

0

Perfect Doug!

Remember to mark this question as solved :)

Regards,

/Kim A

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