how to return different node sets by condition

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AlexR 39 posts 61 karma points

May 07, 2010 @ 12:24
0

How to return different node sets by condition?
If imgId is empty I want get empty node set, but GetMedia return error.

How to return something like next:
```
<xsl:variable name="img" select="if(number($imgId), umbraco.library:GetMedia($imgId, false()), /.. /* empty node-set */ )" />
```
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Tobias Neugebauer 52 posts 93 karma points

May 07, 2010 @ 12:52

Hi,

you can assign a variable by condition like this:

<xsl:variable name="myVar">

    <xsl:choose>

        <xsl:when test="yourCondition">

             <xsl:select .../>

        </xsl:when>

        <xsl:otherwise>

             <xsl:select .../>

        </xsl:otherwise>

    </xsl:choose>

</xsl:variable>

Hope this helps :)

Toby

AlexR 39 posts 61 karma points

May 11, 2010 @ 07:36
0
This isn't help. This return not node set as result.

for example
```
<xsl:variable name="img" select="umbraco.library:GetMedia($imgId, false())" />
```
return node set, but
```
<xsl:variable name="img">
  <xsl:value-of select="umbraco.library:GetMedia($imgId, false())" />
<xsl:variable>
```
doesn't return node set. The second return XML that you can parse to node set.
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Tobias Neugebauer 52 posts 93 karma points

May 11, 2010 @ 08:13
0
Hi,

sorry that didn't do it! Did you try xsl:copy-of instead of xsl:value-of maybe this will do the trick:
```
<xsl:variable name="img">
  <xsl:copy-of select="umbraco.library:GetMedia($imgId, false())" />
<xsl:variable>
```
Cheers, Toby
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