hello,

i'm using the XsltSearch Package and its great. also, for each page (document type) i added new property "contentPageTitle", that contains alternate name to display in the navigation menu (i'm creating page with node name in english and contentPageTitle in hebrew).

in the navigation menu i' doing this:

<xsl:value-of select="$rootTextpageNode/data[@alias='contentPageTitle']/text()"/>
<xsl:if test="string($rootTextpageNode/data[@alias='contentPageTitle']/text()) = ''">    
    <xsl:value-of select="$rootTextpageNode/@nodeName"/>
</xsl:if>

and its works fine.

in the XsltSearch i want to do the same, but i'm dont manage to do that.

instead of:

<!-- page name and url -->
<a href="{umbraco.library:NiceUrl(@id)}" class="xsltsearch_title">
<xsl:value-of select="./@nodeName"/>                                        
 </a>

i want to display the pahe name that stored in the property "contentPageTitle".

how can i do that?

thanks!,

Eran.