how to get umbraco image full file path

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David Armitage 510 posts 2081 karma points

Jul 12, 2016 @ 09:38

Hi,

Please can anyone help. I have been fiddling around far too much trying to figure this out. Any help would be awesome :)

I just want to full file page of an umbraco image Eg C:\Dropbox\Web\sycacouk\Source Code\Website\media\1078\testimage.png

I have manged to write code for a Media item like pdf but the same code just doesn't work for an image

This is the code I used for a file like PDF

public static string GetMediaFilePathById(int Id)
        {
            try
            {
                IMedia media = MediaManager.GetMediaFileById(Id);
                var umbracoFilePath = media.GetValue<string>(Umbraco.Core.Constants.Conventions.Media.File);
                var path = HttpContext.Current.Server.MapPath(umbracoFilePath);
                return path;
            }
            catch
            {
                return string.Empty;
            }
        }

I got errors if I passed an image Id rather than a file Id. I attempted to modify it slightly but no job.

var umbracoFilePath = media.GetValue<string>(Umbraco.Core.Constants.Conventions.MediaTypes.Image);

I googled around and found loads of examples that were old or didn't work. the closet I got to what I want is.

public static string GetImageFilePathById(int Id)
        {
            try
            {
                IMedia media = MediaManager.GetMediaFileById(Id);
                var fullPath = media.GetValue("umbracoFile").ToString();
                return fullPath;
            }
            catch(Exception e)
            {
                return string.Empty;
            }
        }

but this returned a strange string (Not what I want)

{src: '/media/1079/id3232-peter-pan_com.png', crops: []}

Anyone got any idea how to get the full file path either from this string or any other way?

Much Appreciated

David

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David Peck 690 posts 1896 karma points c-trib

Jul 12, 2016 @ 11:04
103
Hi David (great name!!!)

Try this:
```
try
{
    IMedia media = MediaManager.GetMediaFileById(Id);
    var umbracoFile = media.GetValue<string>(Constants.Conventions.Media.File);
    return JsonConvert.DeserializeObject<ImageCropDataSet>(umbracoFile).Src;
 }
 catch(Exception e)
 {
     return string.Empty;
 }
```
You're probably missing a few namespaces there, so if you can't work them out then you can probably grab what you need from my unrelated post from which I grabbed this source code.

David
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David Armitage 510 posts 2081 karma points

Jul 12, 2016 @ 11:30

Hi Dave,

Awesome! Thanks for your help. You save me a heap of time Googling this again tomorrow.

This is exactly what I needed. Just needed to add the MapPath around but nothing major.

public static string GetImageFilePathById(int Id)
        {
            try
            {
                IMedia media = MediaManager.GetMediaFileById(Id);
                var umbracoFile = media.GetValue<string>(Constants.Conventions.Media.File);
                string path = HttpContext.Current.Server.MapPath(JsonConvert.DeserializeObject<ImageCropDataSet>(umbracoFile).Src);
                return path;
            }
            catch (Exception e)
            {
                return string.Empty;
            }
        }

Thanks again. Hope I can re-pay the favor something!

Kind Regards

David

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