HI Mehmet

For creating media you have to use MediaService - https://our.umbraco.org/documentation/reference/management/services/mediaservice

Content service for content items, MediaServices for media and files

There is CreateMedia method that you have to use - https://our.umbraco.org/documentation/reference/management/services/mediaservice#createmedia-string-name-int-parentid-string-mediatypealias-int

After creating media you have to save media id to "mediaPath" property of the document, something like that:

basicContent.SetValue("media", mediaId);

Thanks,

Alex

Hi Mehmet,

Like Alex writes, you first need to upload the the file to the media archive using the media service.

The examples in the documentation could probably be improved a bit, so I've tried to illustrate creating a new media item (image) with the example below:

@{

    // Get a reference to the media service
    IMediaService mediaService = ApplicationContext.Services.MediaService;

    // Declare a path to the local file on the disk
    string path = "D:/photo-1460901419481-3fc27f0cdae9.jpg";

    // Declare the media reference here as we need it later
    IMedia media;

    // Open a new file stream to the file
    using (FileStream fs = new FileStream(path, FileMode.Open)) {

        // Get the file name (aka not the full path)
        string filename = Path.GetFileName(path);

        // Create a new media item of the type "Image" (-1 is the root folder)
        media = mediaService.CreateMedia(filename, -1, Constants.Conventions.MediaTypes.Image);

        // Update the "umbracoFile" property (other properties are then automatically updated as well)
        media.SetValue(Constants.Conventions.Media.File, filename, fs);

        // Save the image
        mediaService.Save(media);

    }

}

Using an overload of the SetValue method, we can point Umbraco to a file in a stream, and Umbraco will then take care of the necessary logic of placing the image file in the correct location within the media archive, as well as update the other properties like width, height and file size.

With the media created, we can then continue to creating or updating your content items. In your other thread, it seemed that you already had creating the content, so the example below assumes that.

The exact value that you should save to your media property depends on the data type of the property. For instance, the default media picker in Umbraco 7.7 and newer will save the media's UDI opposed to the numeric ID of the media in earlier versions.

If the property editor used for the data type is called Umbraco.MediaPicker2, it uses UDIs, whereas Umbraco.MediaPicker saves a numeric ID (see image below for one way to find the name).

The example below assumes you're using Umbraco.MediaPicker2, and thus saves an UDI.

@{

    // Get a reference to the content service
    IContentService contentService = ApplicationContext.Services.ContentService;

    // Get a reference to the content item you wish to update
    IContent content = contentService.GetById(1103);

    // Get the UDI of the media
    GuidUdi mediaUdi = media.GetUdi();

    // We need to convert the UDI to a string, as "SetValue" value doesn't support GuidUdi
    string mediaUdiAsString = mediaUdi.ToString();

    // Update the property value
    content.SetValue("media", mediaUdiAsString);

    // Make sure that we save and publish the change
    contentService.SaveAndPublishWithStatus(content);

}

To summarize both examples (creating media and then updating content), it could look something like this partial view:

@using Umbraco.Core.Services
@inherits UmbracoViewPage

@{

    // Get a reference to the media service
    IMediaService mediaService = ApplicationContext.Services.MediaService;

    // Declare a path to the local file on the disk
    string path = "D:/photo-1460901419481-3fc27f0cdae9.jpg";

    // Declare the media reference here as we need it later
    IMedia media = mediaService.GetById(1147);

    // Open a new file stream to the file
    using (FileStream fs = new FileStream(path, FileMode.Open)) {

        // Get the file name (aka not the full path)
        string filename = Path.GetFileName(path);

        // Create a new media item of the type "Image" (-1 is the root folder)
        media = mediaService.CreateMedia(filename, -1, Constants.Conventions.MediaTypes.Image);

        // Update the "umbracoFile" property (other properties are then automatically updated as well)
        media.SetValue(Constants.Conventions.Media.File, filename, fs);

        // Save the image
        mediaService.Save(media);

    }

    // Get a reference to the content service
    IContentService contentService = ApplicationContext.Services.ContentService;

    // Get a reference to the content item you wish to update
    IContent content = contentService.GetById(1103);

    // Get the UDI of the media
    GuidUdi mediaUdi = media.GetUdi();

    // We need to convert the UDI to a string, as "SetValue" value doesn't support GuidUdi
    string mediaUdiAsString = mediaUdi.ToString();

    // Update the property value
    content.SetValue("media", mediaUdiAsString);

    // Make sure that we save and publish the change
    contentService.SaveAndPublishWithStatus(content);

}

If you're using an API or surface controller instead, the code should look mostly the same.

Hope that helps ;)

Again a question Anders

I did as you wrote. And it run. Thank you so much.

But I have a question

I have a path list which include ".jpg" files.

List<path> pathList = new List<string>();

and I want to loop in list and add all photo in list to my content.

Just I could add only one photo.

Is there any way adding two or more photos to multiple medi pickers ?

is working on a reply...