Hi hetaurhet

Could you show us the code that you've got so far? I think this will help us help you.

And your second question - Yes, you need to insert the macro in one of your templates to make use of your XSLT code.

/Kim A

i have following umediaslider xslt code ...

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet
  version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" xmlns:tagsLib="urn:tagsLib" xmlns:BlogLibrary="urn:BlogLibrary"
  exclude-result-prefixes="msxml  umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes  Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings  Exslt.ExsltSets tagsLib BlogLibrary ">

<xsl:output method="xml" omit-xml-declaration="yes"/>

<xsl:param name="currentPage"/>

<xsl:template match="/">

<!-- start writing XSLT -->
  <xsl:variable name="sliderNode" select="$currentPage/parent::*/child::*[@level=1]"/>

 <div id="slider">
    <div id="imageSlider">
      <xsl:for-each select="$sliderNode/child::umediaSlider">
           <div class="imageSlide">
              <div class="imageSliderInfo">
                  <h2> <xsl:value-of select="@nodeName"/></h2>
                  <xsl:value-of select="teaserText" disable-output-escaping="yes"/>
                </div>
                <div class="imageSliderImage">
                  <img src="{umbracoFile}" width="500" height="320" />
                </div>
            </div>
       
      </xsl:for-each>
   </div>
</div>
</xsl:template>

... under content node I have created node AngerSlider with two sub nodes. what change in xslt I need to do... in template I have inserted macro of the above xslt.

Could you maybe show us your content tree? You probably just haveto change the xPath in the sliderNode-variable. But if You could show us your structure in the content section it would be a little easier. Just somthing like:

- Content

-- Home

--- Some page

--- Another page

etc...

/Kim A

- content

    -- main website node

           --- Home

           --- About us

                   ---- who we are?

    -- my img slider

this is the structure. where my img slider is umedia slider and which I want to use in 'who we are' content page.

Okay I guess that you've got the nodes under the "my img slider"-node?

To get the "my img slider"-node, you should be able to do like this:

<xsl:variable name="sliderNode" select="$currentPage/ancestor-or-self::root/*[@nodeName='my img slider']"/>

I the above example I'm using the node name to match, but a better way would probably be to use the document type alias, if the node has a unique document type.

/Kim A

Thanks Kim it works now...........

Great to hear! I'm glad it works now.

/Kim A

yes its working for any level of node

is working on a reply...