I have problem to grab some element within a foreach.
Basically I only want to see an element:
- if first, or 12th, or 24th, or 36th etc
and
- if 11th, 23rd, 35th etc
I have a hardcoded version, but obviously wrong this way
@foreach (var item in items)
{
if (item.IsFirst() || item.IsPosition(12) || item.IsPosition(24) || item.IsPosition(36) || item.IsPosition(48))
{
show this one
}
if (item.IsPosition(11) || item.IsPosition(23) || item.IsPosition(35) || item.IsPosition(47))
{
show this one too
}
}
Sounds like you just want every 12th item and every 12th item minus one:
var items = new List<string>();
for (var i = 0; i < items.Count; i++)
{
var twelfth = i % 12 == 0;
var minusOne = (i - 1) % 12 == 0 && i > 1;
if (twelfth || minusOne)
{
var item = items[i];
//TODO: Something.
}
}
The percent sign is the mod operator. Alternatively, you could construct your for loop to increment by 12 rather than increment by 1 and you'd have similar results.
Thank you for your help.
Unfortunately I noticed that my basic concept is wrong and can't fit into my idea. So I have a different question, maybe you can help with it.
I would like to render 10 items , after skip 2 items, another 10, another 2 skip.
Foreach show every 12th, 24th, 36st etc elements
Hi,
I have problem to grab some element within a foreach. Basically I only want to see an element: - if first, or 12th, or 24th, or 36th etc and - if 11th, 23rd, 35th etc
I have a hardcoded version, but obviously wrong this way
Does anybody can help me with it?
Sounds like you just want every 12th item and every 12th item minus one:
The percent sign is the mod operator. Alternatively, you could construct your for loop to increment by 12 rather than increment by 1 and you'd have similar results.
Thank you for your help. Unfortunately I noticed that my basic concept is wrong and can't fit into my idea. So I have a different question, maybe you can help with it. I would like to render 10 items , after skip 2 items, another 10, another 2 skip.
Is that possible somehow?
You should be able to use almost the same code that I posted (with a few minor changes to the calculations).
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