access last child in children

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Aaron 5 posts 83 karma points

Oct 28, 2016 @ 14:02
0

Access last child in children

Templates, (partial) views and macros

Umbraco 7
I've created a condition that checks to see if the current child node is the first in the set of children. If it isn't the first child then the URL is generated easily with .Previous().Url. If it is the first child it needs to default to the last child in the set of children.
```
@if( @CurrentPage.Previous() == null ) {
    prevUrl = @CurrentPage.Up().LastChild().Url;
} else {
    prevUrl = @CurrentPage.Previous().Url;
}
```
As you can see above I added .LastChild() after @CurrentPage.Up() knowing that this doesn't work but I thought it would illustrate the desired functionality. I've searched all over for the solution but haven't had any luck yet. Thanks for any help!
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Alex Brown 129 posts 620 karma points

Oct 29, 2016 @ 18:15

0

Would System.Linq.Last() method not work here?

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Dennis Adolfi 1082 posts 6446 karma points MVP 5x c-trib

Oct 31, 2016 @ 08:54

As Alex mentioned, you should be able to use LINQ .Last() in this case. Here is an example of how this could be solved with a little helper:

@helper RenderPrev(IPublishedContent model)
{
    if (model.Parent != null)
    {
        var prevUrl = model.Previous() == null ? model.Parent.Children.Last().Url : Model.Content.Previous().Url;
            <a href="@prevUrl">Previous</a>
    }
}

@RenderPrev(Model.Content)

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Aaron 5 posts 83 karma points

Nov 04, 2016 @ 21:58

1

That worked exactly as needed. Thanks!

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Dennis Adolfi 1082 posts 6446 karma points MVP 5x c-trib

Nov 05, 2016 @ 09:22

0

Awesome! I'm glad I could help and thanks for the response!

Have a great weekend, take care!

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