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  • Bruno Olsen 75 posts 316 karma points
    Jan 04, 2017 @ 10:33
    Bruno Olsen
    0

    xslt to razor help - simple listing grandchildren

    I'm trying to learn razor but keep running into stupid hurdles like this one ;) (I'm thinking this won't be the last post with that intro :D)

    Now, a simple listing of children isn't hard to do - Umbraco even supplies a sample snippet. But what if I want to do something like this:

    <xsl:for-each select="umbraco.library:GetXmlNodeById(xxxx)/*/* [@isDoc]">
    <xsl:if test="position() &lt; 6">
        <xsl:value-of select="@nodeName" />
    </xsl:if>
</xsl:for-each>

    How would that look like in razor?

    Kind regards, Bruno

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  • David Peck 690 posts 1896 karma points c-trib
    Jan 04, 2017 @ 14:48
    David Peck
    0

    Something like:

    @foreach(var grandchild in Umbraco.TypedContent(xxxx).Children().SelectMany( c => c.Children()).Take(6)){
    @grandchild.Name
}
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