Marko Eitel 5 posts 75 karma points

Apr 14, 2017 @ 09:24

Filtering with BeginUmbracoForm

Hello, i stuck on a problem and hope that someone help.

I try to build an Table with Filtering. I'v got a Model, a Controller, a View and a Partial View.

In the View I call the Controller with: Html.RenderAction("Home", "Home");

The Controller built a List with my Model and return it to the Partial View:

public class HomeController : SurfaceController
{

    public ActionResult Home(int? Thema)
    {
        var listSeiteUmb = Umbraco.TypedContent(1057).Children();
        var listThemaUmb = Umbraco.TypedContent(1080).Children();
        var query = from lsu in listSeiteUmb   
                    from ltu in listThemaUmb
                    where lsu.GetPropertyValue<int>("webseiteThema") == ltu.Id
                    select new SeitenViewModel()
                    {
                        Id = lsu.Id,
                        Name = lsu.Name,
                        ThemaName = ltu.Name,
                        ThemaId = ltu.Id
                    };

        var listSeite = query.ToList();
        if (Thema != null)
        {
            listSeite = listSeite.Where(w => w.ThemaId == Thema).ToList();
        }

        return PartialView("_HomeList", listSeite);

    }       
}

My PartialView inherits from

Umbraco.Web.Mvc.UmbracoViewPage<List<Umbraco2.Models.ViewModel.SeitenViewModel>>

and look like this:

Partial: _HomeList

@{

using (Html.BeginUmbracoForm("Home", "Home", FormMethod.Get))
{
    var listThemaUmb = Umbraco.TypedContent(1080).Children();
    var listThema = from ltu in listThemaUmb
                    select new SelectListItem
                    {
                        Text = ltu.Name,
                        Value = ltu.Id.ToString()
                    };
    @Html.Label("Filter")
    @Html.DropDownList("Thema", listThema, "Thema", null);
<br />
<br />
<input type="submit" name="submit" value="Filtern" />
<br />
<br />
<table>
    <thead>
        <tr>
            <th>Seite</th>
            <th>Thema</th>
        </tr>
    </thead>
    @foreach (var item in Model)
    {
        <tr>
            <td>@item.Name</td>
            <td>@item.ThemaName</td>
        </tr>
    }
</table>
}

}

The initialize is correct rendered: I see the View with the Partial View. Screenshot of the correct initial-view

But if I using the Filter and hit the Submit-Button, I see only the (correct filtered) Content of the Partial View. Screenshot after Filtering

How can I render the Partial View WITH the View?

Greetings from Berlin

Marko

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Marc Goodson 2155 posts 14406 karma points MVP 9x c-trib

Apr 16, 2017 @ 18:44

Hi Marko

Yes, a surface controller sits on the 'surface' of a controller, and can only interact with the route, it can't return a view :-(

After a surface controller receives a post from a BeginUmbracoForm form, it can:

return CurrentUmbracoPage(); // returns the current Umbraco page the form is on with the model state intact

or

return RedirectToCurrentUmbracoPage(); // returns the current Umbraco page the form is on but clears the modelstate

see https://our.umbraco.org/documentation/Reference/Templating/Mvc/forms

So this is great for receiving a form post, and sending an email, or adding a record to a database, but not so great for filtering the results on the page you are on.

The options are to either have:

a) Two Surface controllers on the page, one to display the form and dropdown options, kind of as you have it, and as you are making a get request, have a second surface controller child action that reads in the selected filter value from the querystring, and writes out the filtered items...

b) hijack the route, https://our.umbraco.org/Documentation/Reference/Routing/custom-controllers with this techique you create an MVC controller that inhertits from RenderMvcController that is named as docTypeAliasController - where docTypeAlias is the alias of the doc type of the page you want to hijack.

public class HomePageController : BaseController
{

public ActionResult Index(RenderModel model, int themeId=0) { //build your own custom Model that inherits RenderModel var myCustomModel = new myCustomModel(model); myCustomModel.ThemeId = themeId; // populate theme list myCustomModel.ThemeDropdownList = new SelectList()... etc; myCustomModel.FilteredResults = myCustomService.GetFilteredResults(themeId);

// then return the model to your view return CurrentTemplate(myCustomModel);

} }

You view then needs to inherit UmbracoViewPage

or

c) Create an Umbraco API Controller https://our.umbraco.org/documentation/reference/routing/webapi/ that returns the filtered list asynchronously, and wire up javascript to call this api when the dropdown filter is changed.

regards

Marc

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Marko Eitel 5 posts 75 karma points

Apr 18, 2017 @ 22:07

Hello Mark, thanks for the help.

I've rebuilt the Project like Option "b".

But now I have another Problem: I'm using for paging the "X.PagedList.Mvc"-Package. But the Linklist contains a Url.Action-Command, that is not rendered. Any suggestions?

Greetings from Berlin Marko

Update: My solution

Instead of the Url.Action

@Html.PagedListPager( Model, page => Url.Action("Index", new { page }) )

I write the parameter directly:

@Html.PagedListPager((IPagedList)Model, page => ("?page=" + page + "&" + queryString))

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John ben 78 posts 293 karma points

Apr 18, 2017 @ 08:41

Hi Marko I had the same problem u can still use ajax and load a partialView here is an exemple of my code :

 <form action="post">
            <div class="form-group">
                <label for="room">type </label>
                <select class="form-control" id="room">
                    <option value="0">tes</option>
                    <option value="1">test</option>
                    <option value="2">test</option>
                </select>
            </div>
        </form>
 <div id="list"></div>


<script>
$('#room').change(function () {
        var json = null;
        var mylist = parent.document.getElementById("room");
        iterations = mylist.options[mylist.selectedIndex].text;
        var numero = iterations;
        var json = null;
        $.ajax({
            url: '@Url.SurfaceAction("RenderPartialcop", "Cooperation")',
            data: { Coop: numero },
            type: "GET",
            success: function (datad) {
                $('#list').html(datad);
            },
            error: function () {
                alert("Erreur de récupération");
            }
        })
});

in the div list will be loaded ur partialview and it will work perfectly fine, i hope it helped you.

regards.

John ben

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Filtering with BeginUmbracoForm

Partial: _HomeList