Hi Lucy,

Do you have a sample of your code?

Are you using Umbraco 7.6+? If so, MultiNodeTreePicker returns IEnumerable<IPublishedContent>

You can use the Union method to create a union of the results like so:

var mntp1 = Model.Content.GetPropertyValue<IEnumerable<IPublishedContent>>("mntp1");
var mntp2 = Model.Content.GetPropertyValue<IEnumerable<IPublishedContent>>("mntp2");

var union = mntp1.Union(mntp2);

If you just want the string of names:

var names = String.Join(", ", union.Select(m => m.Name));

Hi Matt,

Yes I'm using Umbraco 7.6.6, so I've used IEnumerable<IPublishedContent>

This is my foreach:

    @foreach(var test in SearchResults.Skip((page-1)*numPerPage).Take(numPerPage)){
        var thenode = Umbraco.Content(test.Id);
        var keepcats = thenode.GetPropertyValue<IEnumerable<IPublishedContent>>("keepAChild");
        var testlocs = thenode.GetPropertyValue<IEnumerable<IPublishedContent>>("locations");
        if(!String.IsNullOrWhiteSpace(@keepKey) && !String.IsNullOrWhiteSpace(@countryKey)){ // Has country & keep a child searched
            foreach(var keepitem in keepcats){
                foreach(var locitem in testlocs){
                    if(keepitem.Name == @keepKey && locitem.Name == @countryKey){
                        <p>@thenode.Name | <b>@keepitem.Name</b> | <b>@locitem.Name</b></p>
                    }
                    if(keepitem.Name == @keepKey && locitem.Name != @countryKey){

                        <p>@thenode.Name | <b>@keepitem.Name</b> | @locitem.Name</p>
                    }
                    if(locitem.Name == @countryKey && keepitem.Name != @keepKey){
                        <p>@thenode.Name | @keepitem.Name | <b>@locitem.Name</b></p>
                    }
                }
            }
        }
    }

I've just tried using Union but I get this error:

CS1977: Cannot use a lambda expression as an argument to a dynamically dispatched operation without first casting it to a delegate or expression tree type

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