Hi Marc,

Thank you for your reply.

Unfortunately this didn't work for me, The solution that did i've marked below :)

Many thanks again!

Sam

The code:

//This is the Business Guid
var businessGuid = member.GetValue<string>("business");

//Marc Forum solution
var pickedMemberId = businessGuid;
var pickedMember = Umbraco.TypedMember(pickedMemberId);

if (pickedMember != null)
{
    var memberName = pickedMember.Name;
    var someProperty = pickedMember.GetPropertyValue<string>("business");

    <p>@memberName</p>
    <p>@someProperty</p>
}

Hi Bjarne,

The below code worked for me!

As you suggested i just needed to use the IPublishedContent.

Below is the code that worked:

@{
var currentMember = Members.GetCurrentMember();
var business = currentMember.GetPropertyValue<IPublishedContent>("business");

if (business != null)
{
    var name = business.Name;
    <p>@name</p>
}

--Side note-- If i wanted to get the same values in a controller to pass to a model, how would i do this?

Currently i am

1. Getting the memberId.
2. Then getting the Guid.
3. Stripping off 'umb://member/' from the Guid
4. Writing a SQL query to get the name of the business from the text column in umbracoNode table WHERE Guid = Guid.
5. Then saving that string value for business name.

Is there an easier way?

Many thanks,

Sam.

Hi Sam

I you have either a custom controller as a RenderMvcController for your page https://our.umbraco.com/documentation/reference/routing/custom-controllers or a SurfaceController which is a part of the page https://our.umbraco.com/documentation/reference/routing/surface-controllers for part of your page e.g. with a form or another component, then you should be able to either get the property on the current member or getting a specific member and map these values to your custom model.

If you are using a Member Picker (Umbraco.MemberPicker2), you should be able to get it the selected member by using either .GetPropertyValue<IPublishedContent>("business") or .GetPropertyValue<IEnumerable<IPublishedContent>>("business"), but first you need to get the member (or content node) with this property.

If you are using ModelsBuilder Dll mode, you can use something like this if you deal with a specific member type:

var member = Members.GetCurrentMember();
var customer = member.OfType<Umbraco.Web.PublishedContentModels.Customer>();
if (customer != null)
{
    var business = customer.Business;
}

/Bjarne

Hi Bjarne,

I will give this a try and let you know how i get on :)

Many thanks, Sam

Hi Bjarne,

This solution worked perfectly!

Thank you

Sam